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lys-0071 [83]
3 years ago
8

All plants and animals need energy in order to survive. The diagram above shows how energy gets transferred among living things

in a particular ecosystem. If all of the grasshoppers were removed from the region, which type of organism in this ecosystem would not be able to survive?
A.frogs and spiders


B.frogs, spiders, and wasps

C.spiders only

D.frogs only
PLEASE HURRY
Chemistry
1 answer:
Andre45 [30]3 years ago
8 0
I believe it would be A, frogs and spiders, because frogs and spiders both eat grasshoppers. But I cannot see the diagram it talks about, so it's harder to tell.
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If you add enzyme to a solution containing only the product(s) of a reaction, would you expect any substrate to form?
Masteriza [31]

Answer:

e

Explanation:

<em>Provided the reaction that leads to the formation of the products can proceed in both forward and backward directions, the correct answer would be yes because the reaction will proceed backward until equilibrium is reached.</em>

<u>For a reaction that can proceed both forward and backward, the addition of a catalyst increases the rate of reaction in both directions based on the fact that a catalyst cannot alter the equilibrium of a reaction. </u>

Hence, if an enzyme is added to the product of a reaction that has the potential to proceed in both forward and reverse reactions, a substrate would be expected to form because the reaction will proceed backward until an equilibrium is reached.

The correct option is e.

8 0
3 years ago
How many moles are in 3.00x 10^22 atoms of He?
sp2606 [1]

Answer:

<h2>0.05 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{3.0 \times  {10}^{22} }{6.02 \times  {10}^{23} }  \\  = 0.049833...

We have the final answer as

<h3>0.05 moles</h3>

Hope this helps you

3 0
3 years ago
The charge of the stable ion of S and Li?
balandron [24]

Answer:

sulfur will have a chafge of -2 and Lithium will have a charge of +1

3 0
3 years ago
Which of the following elements can form diatomic molecules held together by triple covalent bonds?
Art [367]
Nitrogen can form a diatomic molecule held together by triple bonds.
6 0
2 years ago
Read 2 more answers
A sample of HI (9.30×10^−3mol) was placed in an empty 2.00 L container at 1000 K. After equilibrium was reached, the concentrati
Sedaia [141]

Answer:

The answer is "29.081"

Explanation:

when the empty 2.00 L container of 1000 kg, a sample of HI (9.30 x 10-3 mol) has also been placed.  

\text{calculating the initial HI}= \frac{mol}{V}

                                       =\frac{9.3 \times 10 ^ -3}{2}

                                      =0.00465 \ Mol

\text{Similarly}\ \  I_2 \ \  \text{follows} \ \  H_2 = 0 }

Its density of I 2 was 6.29x10-4 M if the balance had been obtained, then we have to get the intensity of equilibrium then:

HI  = 0.00465 - 2x\\\\ I_{2}  \ eq = H_2 \ eq = 0 + x \\\\

It is defined that:

I_2 = 6.29 \times 10^{-4}  \ M \\\\x = I_2 \\\\

HI \ eq= 0.00465 - 2x \\

          =0.00465 -2 \times 6.29 \times 10^{-4} \\\\ =  0.00465 -\frac{25.16 }{10^4}  \\\\   = 0.003392\  M

Now, we calculate the position:  

For the reaction H 2(g) + I 2(g)\rightleftharpoons  2HI(g), you can calculate the value of Kc at 1000 K.  

data expression for Kc

2HI \rightleftharpoons  H_2 + I_2 \\\\\to Kc = \frac{H_2 \times I_2}{HI^2}

         = \frac{6.29\times10^{-4} \times 6.29 \times 10^{-4}}{0.003392^2} \\\\= \frac{6.29\times 6.29 \times 10^{-8}}{0.003392^2} \\\\= \frac{39.564 \times 10^{-8}}{1.150 \times 10-5} \\\\= 0.034386

calculating the reverse reaction

H_2(g) + I_2(g)\rightleftharpoons  2HI(g)

Kc = \frac{1}{Kc} \\\\

     = \frac{1}{0.034386}\\ \\= 29.081\\

7 0
3 years ago
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