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LenaWriter [7]
3 years ago
8

The final charge on each of the three separated spheres in part (b) is +3.0 μC. How many electrons would have to be added to one

of these spheres to make it electrically neutral?
Chemistry
1 answer:
marishachu [46]3 years ago
4 0

Answer:

1.873\times 10^{13} electrons should be added to one of these spheres to make it electrically neutral.

Explanation:

Total charge on each sphere =  +3.0 μC =3\times 10^{-6} C

1 \mu C=10^{-6} C

In order to neutralize the positive charge equal magnitude of negative charge is to be added.

Total charge electrons, Q=  -3.0 μC =-3\times 10^{-6} C

Number of electrons = n

Charge on a single electron, e = -1.602\times 10^{-19} C

Q = n × e

-3\times 10^{-6} C=n\times (-1.602\times 10^{-19} C)

n=\frac{-3\times 10^{-6} C}{-1.602\times 10^{-19} C}=1.873\times 10^{13}

1.873\times 10^{13} electrons should be added to one of these spheres to make it electrically neutral.

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