Question

The final charge on each of the three separated spheres in part (b) is +3.0 μC. How many electrons would have to be added to one of these spheres to make it electrically neutral?

Answer 1

Answer:

$1.873\times 10^{13}$ electrons should be added to one of these spheres to make it electrically neutral.

Explanation:

Total charge on each sphere =  +3.0 μC =$3\times 10^{-6} C$

$1 \mu C=10^{-6} C$

In order to neutralize the positive charge equal magnitude of negative charge is to be added.

Total charge electrons, Q=  -3.0 μC =$-3\times 10^{-6} C$

Number of electrons = n

Charge on a single electron, e = $-1.602\times 10^{-19} C$

Q = n × e

$-3\times 10^{-6} C=n\times (-1.602\times 10^{-19} C)$

$n=\frac{-3\times 10^{-6} C}{-1.602\times 10^{-19} C}=1.873\times 10^{13}$

$1.873\times 10^{13}$ electrons should be added to one of these spheres to make it electrically neutral.