Question

Find the range of h(x)=x^2 + 2x - 5 when the domain is {-4,-2,0,2}

Answer 1

The range is: {3,-5}

Step-by-step explanation:

Given

$h(x)=x^2 + 2x - 5$

We will get the range by putting the values given in domain in the function

Putting x=-4

$h(-4)=(-4)^2 + 2(-4) - 5\\=16-8-5\\=16-13\\=3$

Putting x=-2

$h(-2)=(-2)^2 +2(-2) - 5\\=4-4-5\\=0-5\\=-5$

Putting x=0

$h(0)=(0)^2 + 2(0) - 5\\=0+0-5\\=-5$

Putting x=2

$h(2)=(2)^2 + 2(2) - 5\\=4+4-5\\=8-5\\=3$

The range is: {3,-5}

Keywords: Functions, Range

Learn more about range at:

• brainly.com/question/5528742
• brainly.com/question/5533462

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