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alina1380 [7]
3 years ago
10

How long will each person take to run a total of 50 miles at the given rates?

Mathematics
1 answer:
forsale [732]3 years ago
6 0
Problema Solution

Terrance and Jesse are training for a long-distance race. Terrance trains at a rate of 6 miles every half hour, and Jesse trains at a rate of 2 miles every 15 minutes.

How long will each person take to run a total of 50 miles at the given rates?

Answer provided by our tutors

d = 50 mi the distance
t1 = the time of Terrance
t2 = the time of Jesse
Terrance trains at a rate of 6 miles every half hour thus his rate is:
v1 = 6/0.5 = 12 mph
Jesse trains at a rate of 2 miles every 15 minutes thus his rate is:
v2 = 2/(15/60) = 8 mph
since speed = distance/time follows time = distance/speed:
t1 = d/v1
t1 = 50/12
t1 = 4 1/6 hr
t1 = 4 hr 10 min
t2 = d/v2
t2 = 50/8
t2 = 6 1/4 hr
t2 = 6 hr 15 min
Terrance will run 4 hours and 10 minutes.
Jesse will run 6 hours and 15 minutes.

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Option B: g(x) = |x+4| -10 is the equation which represents the function graphed on the coordinate plane.

<h3>How to know what function is graphed on the coordinate plane?</h3>

We see what points it goes through, what type of nature it is showing where (like for example, the given function firstly goes down straightly, then rise up straightly after x = -4 ). We can see on what value of x, does the function become 0.

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The graph contains straight lines, so it must be linear.

The graph contains a twist in the direction where it was going initially and changes the direction. This shows that the graph is using something else than just a regular linear equation.

The graph turns up after it goes through x = -4.

Let we try to make equation of straight lines before and after x = -4 which the graph follows.

The first line goes 1 block down (1 block is of 2 units) on y axis as we go 1 block left on x axis. Thus the slope will be -2/2 = -1 (we take slope as rise/run and since rise was down thus it is taken as -ve rise).

The slope intercept form of this line would be

y = mx + c\\&#10;y = -x + c

Since the line passes through point x = -4, y = -10, thus this point must satisfy the equation of that line since an equation represents the family of points which  make up the given line.

Thus,

y = -x + c\\&#10;-10 = -(-4) + c\\&#10;-10 = 4 + c\\&#10;c = -10 -4 \\&#10;c = -14

Thus, the equation of first line would be y = -x -14

The equation of second line, let be y = mx + c.

Since the second line intersects the y axis at y = -6, thus the y intercept of this line is -6 or c = -6.

Since the line rises 1 block( = 2 units) as one block of run happens on x axis in left direction (we take left as positive and right direction run as negative. This is standard sign convention used by most of the mathematical community. Conventions are just to remove ambiguity on international level). Thus, the slope of this line is 2/2 = 1

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y = x - 6

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y = -x -14\\&#10;and \\&#10;y = x -6\\&#10;\\\\&#10;y = -x -10 -4\\&#10;and\\&#10;y = x - 10 + 4\\&#10;\\\\&#10;y = -10 - (x + 4)\\&#10;and\\&#10;y = -10 + (x + 4)

But the graph has first line till x <= -4 and second line from x >= -4

Thinking carefully on this fact, we can see that when x <= -4 in first line, the -(x+4) is positive or 0

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the (x+4) is positive or 0

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y = -10 + |x+4|

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Note that at x = -4, both the lines have y = -10.

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