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3 years ago

A tutor gives John 5 assignments and asks him to complete 5. How many possible combinations? Pls answer ASAP

Mathematics

1 answer:

Fittoniya [83]3 years ago

7 0

Answer:

There is 1 possible combination

Step-by-step explanation:

There are 5 assignments and they must be completed. 5. We want to find the number of combinations, then we use the formula of combinations.

$nCr =\frac{n!}{r!(n-r)!}$

Where n is the total number of objects and you choose r from them

Then

$n= 5\\\\r = 5$

$5C5 =\frac{5!}{5!(5-5)!}$

$5C5 =\frac{5!}{5!(0)!}$

$5C5 =\frac{5!}{5!}$

$5C5 =1$

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3 years ago

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Step-by-step explanation:

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3 years ago

. Let X and Y be random variables of possible percent returns (0%, 10%,

bazaltina [42]

(a) The marginal distribution of X is

Pr(X = x) = ∑ Pr(X = x, Y = y)

… = 0.0625 + 0.0625 + 0.0625 + 0.0625

… = 0.25

That is, the first equality follows from the law of total probability, with the sum taken over y from {0, 5, 10, 15}. Each probability Pr(X = x, Y = y) is given in the table to be 0.0625.

Similarly, the marginal distribution of Y is

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(b) Yes, they're independent because

Pr(X = x, Y = y) = 0.0625,

and

Pr(X = x) Pr(Y = y) = 0.25 • 0.25 = 0.0625.

E[X] = ∑ x Pr(X = x)

… = 0.25 ∑ x

… = 0.25 (0 + 5 + 10 + 15)

… = 7.5

and you would find the same mean for Y,

E[Y] = 7.5

The variance of X is

V[X] = E[X^2] - E[X]^2

… = (∑ x^2 Pr(X = x)) - 7.5^2

… = 0.25 (∑ x^2) - 56.25

… = 0.25 (0^2 + 5^2 + 10^2 + 15^2) - 56.25

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and similarly,

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3 years ago

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erastovalidia [21]

Answer:

Option A

Step-by-step explanation:

Number of employees exceeded their sales quota = 17

Number of employees met their sales quota = 13

Number of employees didn't exceed their sales quota = 3

Now, we need to find the ratio of the number employees who exceeded their sales quota to the number of employees who didn't exceed their sales quota,

$17:13 + 3\\=17:16$

So, Option 'A' is correct.

Please mark as Brainliest!!

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3 years ago