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3 years ago

Can someone help me with this. will give you brainliest.

Mathematics

2 answers:

VashaNatasha [74]3 years ago

8 0

For number one the answer is the first one.

For number two the third option is the correct one.

Elodia [21]3 years ago

7 0

1. A. Hypotenuse: HG; Legs: IG and HI

2. C. Hypotenuse: AC; Legs: AB and BC

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Factor Completely: 12x2 + 22x + 6 A) (2x+ 3)(6x + 2) B) 6(x + 1)(2x + 1) C) 2(2x + 3)(3x + 1) D) 2(2x + 1)(3x + 3)

tia_tia [17]

Answer:

C) 2 (2x + 3) (3x + 1)

Step-by-step explanation:

12x² + 22x + 6

2 ( 6x² + 11x + 3 )

2 [ 6x² + 9x + 2x + 3 ]

2 [ 3x ( 2x + 3 ) + 1 ( 2x + 3 ) ]

2 ( 2x + 3 ) ( 3x + 1 ) ⇒ C

7 0

4 years ago

What is the equation of the line that passes through the point (-3, 2) and has a<br> slope of -2/3

Mazyrski [523]

Answer:

y=-2/3x

Step-by-step explanation:

if you use the graphing calculator, the y intercept of the equation is 0 therefore y=mx

m=-2/3

the slope intercept equation is y=-2/3x

5 0

3 years ago

WILL GIVE BRAINLIEST DUE NOW!!!!!! Which activities best support development of cardiorespiratory fitness? (5 points) a Push-ups

Ilia_Sergeevich [38]

Answer:

c Aerobics and jumping rope

Thank you and please rate me as brainliest as it will help me to level up

7 0

3 years ago

A restaurant had 1/3 tray of baked pasta left over after dinner. If 6 workers share the remaining pasta equally, what fraction o

rosijanka [135]

Answer:

1/3÷6

1/3 x 1/6

Step-by-step explanation:

You want to get an answer of 1/18, which these equations give.

5 0

2 years ago

Hello I need help Finding the probability

Stolb23 [73]

Each petal of the region $R$ is the intersection of two circles, both of diameter 10. Each petal in turn is twice the area of a circular segment bounded by a chord of length $5\sqrt2$ , which implies the segment is subtended by an angle of $\dfrac\pi2$ . This means the area of the segment is

$\text{area}_{\text{segment}}=\text{area}_{\text{sector}}-\text{area}_{\text{triangle}}$
$\text{area}_{\text{segment}}=\dfrac{25\pi}4-\dfrac{25}2$

This means the area of one petal is $\dfrac{25\pi}2-25$ , and the area of $R$ is four times this, or $50\pi-100$ .

Meanwhile, the area of $G$ is simply the area of the square minus the area of $R$ , or $10^2-(50\pi-100)=200-50\pi$ .

So

$\mathbb P(X=R)=\dfrac{50\pi-100}{100}=\dfrac\pi2-1$
$\mathbb P(X=G)=\dfrac{200-50\pi}{100}=2-\dfrac\pi2$
$\mathbb P((X=R)\land(X=G))=0$ (provided these regions are indeed disjoint; it's hard to tell from the picture)
$\mathbb P((X=R)\lor(X=G))=\mathbb P(X=R)+\mathbb P(X=G)=1$

4 0

4 years ago