Answer: The distance from each side of the bench to the edges of the platform = 16.85 feet.
Explanation:
Length of platform = 40.75 feet
Length of bench = 7.05 feet
Let the distance from each side of the bench to the edges of the platform be x
So, it becomes x+7.05+x = 40.75
⇒2x+7.05= 40.75
⇒2x = 40.75- 7.05
⇒x = 33.7
⇒x=
⇒x= 16.85 feet .
So, the distance from each side of the bench to the edges of the platform = 16.85 feet.
-5 I think
Ignore this this is just for 20 words
Answer:
The math club has 22 students, and the art club has 34 students.
Step-by-step explanation:
Given that there are a total of 56 students between the art club and the math club, and that the art club has 12 more students than the math club, to determine how many students there are in each club, the following calculation must be performed:
X + X + 12 = 56
2X + 12 = 56
2X = 56 - 12
X = 44/2
X = 22
Thus, the math club has 22 students, and the art club has 34 students.
Answer:
<h2>D.

or StartFraction x squared + 3 x minus 12 Over (x + 3) (x minus 5) (x + 7) EndFraction</h2>
Step-by-step explanation:
Given the expression
, the dfference is expressed as follows;
Step1: First we need to factorize the denominator of each function.

Step 2: We will find the LCM of the resulting expression

The final expression gives the difference
The transitive property is a chain rule for the variables a, b and c.
It states that if a is equal to b and b is equal to c then a is equal to c.
If a = b and b = c then a = c.