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Sidana [21]
4 years ago
7

]2 QUESTIONS]

Chemistry
2 answers:
Ivanshal [37]4 years ago
8 0
1) a mixture is a substance made by mixing other substances together

2) yes, there are many different methods. some examples are: paper chromatography, filtration, evaporation and magnetism
Tcecarenko [31]4 years ago
7 0
A mixture could be for example sand and water , it could be separated using filter paper. When the sand and water are poured through the filter paper they separate
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Match each body system with its main organ.
olya-2409 [2.1K]

Answer:

it's in the explanation

Explanation:

Lungs- Respiratory

Heart- Circulatory

Brain- Nervous

Stomach- Digestive

Bladder- Excretory

7 0
3 years ago
1. A 25 g rock is placed in a graduated cylinder with water. The volume of the liquid rises from 18.3 mL to 21.4 mL Calculate th
MaRussiya [10]

Answer:

1. \rho=8.06g/cm^3

2. H=10cm

Explanation:

Hello,

1. In this case, since the volume of the rock is obtained via the difference between the volume of the cylinder with the water and the rock and the volume of the cylinder with the water only:

V=21.4mL-18.3mL=3.1mL

Thus, the density turns out:

\rho=\frac{m}{V}=\frac{25g}{3.1cm^3}  \\\\\rho=8.06g/cm^3

2. In this case, given the density and mass of aluminum we can compute its volume as follows:

V=\frac{m}{\rho}=\frac{1080g}{2.7g/cm^3}=400cm^3

Moreover, as the volume is also defined in terms of width, height and length:

V=W*H*L

The height is computed to be:

H=\frac{V}{L*W}=\frac{400cm^3}{5cm*8cm}\\ \\H=10cm

Best regards.

3 0
3 years ago
Calculate the density of a substance with a mass of 0.0500g and volume of 6.40mL, round to the correct number of significant num
lozanna [386]
Density=mass/volume
Mass = 0.0500g
Volume = 6.40mL

0.0500g/6.40mL = 0.0078g/mL
5 0
3 years ago
Help! Homework due tomorrow ​
slavikrds [6]
You put precipitation in the wrong place the answer is D+A (number 4)
8 0
2 years ago
Read 2 more answers
How many moles of chloride ions are there in 2.5 L of 5 M magnesium chloride?
castortr0y [4]

Answer:

n_{Cl^-}=25molCl^-

Explanation:

Hello,

In this case, since the given 5-M concentration of magnesium chloride is expressed as:

5\frac{molMgCl_2}{L}

We can notice that one mole of salt contains two moles of chloride ions as the subscript of chlorine is two, in such a way, with the volume of solution we obtain the moles of chloride ions as shown below:

n_{Cl^-}=5\frac{molMgCl_2}{L}*\frac{2molCl^-}{1molMgCl_2} *2.5L\\\\n_{Cl^-}=25molCl^-

Best regards.

4 0
3 years ago
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