Answer:
CO₂. Option B.
Explanation:
We can use the Ideal Gases Law to solve this question
Formula: P . V = n. R . T
First of all, we convert the T° from °C to K
T°C + 273 → 0°C + 273 = 273K
Let's replace data: 15 atm . 0.7462 L = n . 0.082 L.atm/mol.K . 273K
15 atm . 0.7462 L / (0.082 L.atm/mol.K . 273K) = n
0.500 mol = n
These moles are the amount for 22 g of gas. Let's determine the molar mass to find out the gas → molar mass = g/mol
22 g /0.5m = 44g/mol
This molar mass corresponds to CO₂
Answer:
0.010g of C-14 would be later after 50,000 years
Explanation:
The kinetics of radioactive decay follows the equation:
Ln (N / N₀) = -kt
<em>Where N could be taken as mass after time t, </em>
<em>N₀ initial mass = 4.30g;</em>
k is rate constant = ln 2 / t(1/2)
<em>= ln 2 / 5730years = 1.2097x10⁻⁴ years ⁻¹</em>
<em />
Replacing:
Ln (N / 4.30g) = -1.2097x10⁻⁴ years ⁻¹ * 50000 years
N / 4.30 = 2.36x10⁻³
N =
<h3>0.010g of C-14 would be later after 50,000 years</h3>
A2+. Group 2 elements form cations with 2+ charge.
As it is located at 7s ^2 it will have 2 valence electrons that due to its position in the s orbital it will be prone to losing them to obtain a noble gas configuration.
