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dusya [7]
3 years ago
8

Which of the following has the units of g/mol?

Chemistry
1 answer:
o-na [289]3 years ago
6 0

Answer: molar mass

Explanation:

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In simple diffusion, small molecules without charges such as oxygen and carbon dioxide flow through a plasma membrane without assistance and without expending energy. Other substances such as proteins<span>, glucose and charged particles called ions cannot pass through the selectively permeable membrane.</span>
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3 years ago
A1(NO3)3 name, formula for cation an formula for anion
Nostrana [21]

Answer:

Explanation:

The name of the compound is:

       Al(NO₃)₃ is Aluminium nitrate

Aluminium nitrate is an ionic compound formed when Al loses 3 valence electrons to the nitrate.

Formula of cation: A cation is a positive charged specie

              Al³⁺

 Formula of anion: Anion is a negatively charged specie;

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7 0
3 years ago
What is the number of moles of solute in 250 mL of a .80M solution
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Answer:

There are 0.1 moles of solute in 250 mL of 0.4 M solution

Explanation:

because it is

8 0
3 years ago
HELP PLEASE!!! FIRST PERSON TO ANSWER GETS 90 POINTS AND MARKED BRAINLIEST!
3241004551 [841]

Answer:

MgO has a highest melting point

C5Br has lowesst

Explanation:

It takes a lot of energy to overcome the strong electrostatic forces of attraction between oppositely charged ions, so ionic compounds have high melting and boiling points. ... Magnesium oxide is made from ions with two charges (Mg 2+ and O 2-) and so has a much higher melting point of 2852°C.

3 0
3 years ago
What is the concentration of the hydroxide ion? Given that the concentration of the hydronium ion is 2.3 X 10^-7 M
professor190 [17]

Answer:

4.35 * 10^-8 M

Explanation:

Since the concentration of the hydronium ion= 2.3 X 10^-7 M

And we know that;

[H3O^+] [OH^-] = 1 * 10^-14

[H3O^+]  = concentration of the hydronium ion

[OH^-] = concentration of the hydroxide ion

So;

[OH^-] =1 * 10^-14/[ H3O^+]

But [H3O^+] = 2.3 X 10^-7 M

[OH^-] = 1 * 10^-14/2.3 X 10^-7

[OH^-] = 4.35 * 10^-8 M

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3 years ago
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