I really need help please help me out!

$\begin{array}{cccc}{Score\ Interval} & {f} & {Proportion} & {Percentage} & {9-10} & {29} &{0.19} & {19\%} & {7-8} & {53} & {0.34} & {34\%} &{5-6}& {50} & {0.32} & {32\%} &{3-4} & {22} & {0.14} & {14\%} & {1-2} & {1} & {0.01} & {1\%} \ \end{array}$

Step-by-step explanation:

Given

$\begin{array}{cccc}{Score\ Interval} & {f} & {Proportion} & {Percentage} & {9-10} & {29} &{0.19} & {19\%} & {7-8} & {53} & {} & {} &{5-6}& {50} & {} & {} &{3-4} & {22} & {0.14} & {14\%} & {1-2} & {1} & {0.01} & {1\%} \ \end{array}$

Required

Fill in the gaps

First, we calculate the total frequency:

$Total = \sum f$

$Total = 29+53+50+22+1$

$Total = 155$

The proportion (p) is calculated by:

$p = \frac{f}{Total}$

The percentage (P) is calculated by:

$P = p * 100\%$

For interval 7 - 8, we have:

$p = \frac{53}{155} = 0.34$

$P = 0.34 * 100\% = 34\%$

For interval 5 - 6, we have:

$p = \frac{50}{155} = 0.32$

$P = 0.32 * 100\% = 32\%$

So, the complete table is:

$\begin{array}{cccc}{Score\ Interval} & {f} & {Proportion} & {Percentage} & {9-10} & {29} &{0.19} & {19\%} & {7-8} & {53} & {0.34} & {34\%} &{5-6}& {50} & {0.32} & {32\%} &{3-4} & {22} & {0.14} & {14\%} & {1-2} & {1} & {0.01} & {1\%} \ \end{array}$

6 0

2 years ago

Given: SR bisects angle TSQ angle T is congruent to angle Q prove: triangle RTS is congruent to RQS

yan [13]

Triangle RTS is congruent to RQS by AAS postulate of congruent

Step-by-step explanation:

Let us revise the cases of congruence

SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and including angle in the 2nd Δ
ASA ⇒ 2 angles and the side whose joining them in the 1st Δ ≅ 2 angles and the side whose joining them in the 2nd Δ
AAS ⇒ 2 angles and one side in the 1st Δ ≅ 2 angles and one side in the 2nd Δ
HL ⇒ hypotenuse leg of the 1st right Δ ≅ hypotenuse leg of the 2nd right Δ

∵ SR bisects angle TSQ ⇒ given

∴ ∠TSR ≅ ∠QSR

∴ m∠TSR ≅ m∠QSR

∵ ∠T ≅ ∠Q ⇒ given

∴ m∠T ≅ m∠Q

In two triangles RTS and RQS

∵ m∠T ≅ m∠Q

∵ m∠TSR ≅ m∠QSR

∵ RS is a common side in the two triangle

- By using the 4th case above

∴ Δ RTS ≅ ΔRQS ⇒ AAS postulate

Triangle RTS is congruent to RQS by AAS postulate of congruent

Learn more:

You can learn more about the congruent in brainly.com/question/3202836

#LearnwithBrainly

3 0

3 years ago