Question

Determine whether 81a2 − 25z6 is a difference of two squares. If so, factor it. If not, explain why.

Answer 1

81 a² - 25 $z^{6}$ is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)

Step-by-step explanation:

The difference of two squares is a binomial of two terms each term is a square and the sign between the two terms is (-), its factorization is the product of two identical binomials with different middle signs

• a² - b² is a difference of two squares
• a² - b² = (a + b)(a - b)

∵ The binomial is 81 a² - 25 $z^{6}$

∵ $\sqrt{81}$ = 9

∵ $\sqrt{a^{2} }$ = a

∴ $\sqrt{81a^{2}}=9a$

∵ $\sqrt{25}$ = 5

∵ $\sqrt{z^{6}}$ = z³

∴ $\sqrt{25z^{6}}=5z^{3}$

- The two terms have square root

∵ The sign between them is (-)

∴ 81 a² - 25 $z^{6}$  is a difference of two squares

∵ Its factorization is two identical brackets with different

   middle signs

∵ 81 a² = 9a × 9a

∵ 25 $z^{6}$ = 5z³ × 5z³

- The terms of the two brackets are 9a and 5z³

∴ 81 a² - 25 $z^{6}$ = (9a + 5z³)(9a - 5z³)

81 a² - 25 $z^{6}$ is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)

Learn more:

You can learn more about the difference of two squares in brainly.com/question/1414397

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