Answer:
2 wrongly solutions and 18 right solutions
Step-by-step explanation:
The computation is shown below:
= 20 (problems) × 10 (points)
= 200 points
And it received 176 points
So the difference is of
= 200 - 176
= 24
In the case of wrong solution, the points that are lost is
= 10 + 2
= 12
Now the solutions done wrongly is
= 24 ÷ 12
= 2
And, the solutions does rightly is
= 20 - 2
= 18
The distance formula for two points in a plane is
D=sqrt( (x1-x2)^2 + (y1-y2)^2 )
From T to U
D= sqrt((80-20)^2 + (20-60)^2) = 72.11
Then flying from U to V
D= sqrt((20-110)^2 + (60-85)^2) = 93.4
So T to U to V = 72.11+93.4 = 165.5
BUT checking also T to V to U
From T to V
D= sqrt((80-110)^2 + (20-85)^2) = 71.6
Then from V to U
D= sqrt((110-20)^2 + (85-60)^2) = 93.4
So from T to V to U = 165
Pretty much the same both directions
So yes the answer is A
Answer:

Step-by-step explanation:
The sum is larger than 9, it means we have: 10, 11, and 12
- To get the outcome is 12, we have only one way is that the two dice shows face-6. The probability to have 12 is:
P(12) =
=
- To get 11, we have it two ways once dice shows face-5 and the other shows face-6 and vice versa
P(11) = 2*
= 
- To get 10, we have it three ways ( once dice shows face-5 and the other shows face-6 and vice versa , two dice show 5)
P(10) = 3*
=
So the probability of getting a number larger than 9 for the first time on the third roll is:
P(12) + P(11) +P(10 )
=
+
+
= 
Answer:
Step-by-step explanation:
It is vital to first find the gradient/ slope between the points

let us use the point (6,1) to find the value of c
y=mx+c
1=1(6)+c
1-6=c
∴c=-5
the equation is given by
y=x-5