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Luden [163]
3 years ago
5

1. How is pressure affected as depth increases? Answer:

Chemistry
1 answer:
sergiy2304 [10]3 years ago
4 0

Answer:

The increase in pressure is due to the hydrostatic pressure

Explanation:

As we go down there is high force exerted on the object by the water and the pressure also increase

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Given that the molar mass of carbon is 12 g/mol and the molar mass of oxygen is 16 g/mol, calculate the molar mass of carbon dio
nekit [7.7K]
Molar mass of oxygen is:
M(O)=16 g/mol
Molar mass of carbon is:
M(C)=12 g/mol  
Molar mass of carbon dioxide is:
M(CO2)=M(C)+2*M(O)
 M(CO2)=12 g/mol+2*16g/mol
M(CO2)=44 g/mol

<span>Molar mass(M) is the mass of 1 mole of the substance (grams per mole of a compound).</span>
7 0
4 years ago
Table 2 Heat of Reaction of NaOH (aq) and HCl(aq) Solution
kondaur [170]

Answer:

the molarity of NaOH is 1.10. And the molarity of HCl is 1.10. And the initial Temp=0.50(°c). and The final Temp= 1.10(°c)

8 0
3 years ago
Chemical formula of ammonium oxide
11111nata11111 [884]

The answer is (NH4)2O

8 0
3 years ago
What things typically are counted in multiples or fractions of moles
ololo11 [35]

Answer:

Individually well, defined identical chemically units such as molecules, ions, atoms, or electrons

Explanation:

The mole is used as the unit of measurement for substance such as molecules, ions, atoms, or electrons. One mole of a substance is equivalent to 6.02×10²³ particles of the substance. The number, 6.02 × 10²³ is known as Avogadro's number.

The particles quantified as moles are individually well, defined identical chemically units such that the mole can be used to describe a part of a substance or the whole substance consisting of several moles of the substance combined.

7 0
3 years ago
2.00 L of 0.800 M NaNO3 must be prepared from a solution known to be 2.50 M in concentration.How many mL are required? Plus don'
Morgarella [4.7K]

Answer:

1.36 × 10³ mL of water.

Explanation:

We can utilize the dilution equation. Recall that:

\displaystyle M_1V_1= M_2V_2

Where <em>M</em> represents molarity and <em>V</em> represents volume.

Let the initial concentration and unknown volume be <em>M</em>₁ and <em>V</em>₁, respectively. Let the final concentration and required volume be <em>M</em>₂ and <em>V</em>₂, respectively. Solve for <em>V</em>₁:

\displaystyle \begin{aligned} (2.50\text{ M})V_1 &= (0.800\text{ M})(2.00\text{ L}) \\ \\ V_1 & = 0.640\text{ L} \end{aligned}

Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus:
\displaystyle 2.00\text{ L} - 0.640\text{ L} = 1.36\text{ L}

Convert this value to mL:
\displaystyle 1.36\text{ L} \cdot \frac{1000\text{ mL}}{1\text{ L}} = 1.36\times 10^3\text{ mL}

Therefore, about 1.36 × 10³ mL of water need to be added to the 2.50 M solution.

8 0
2 years ago
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