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3 years ago

What will happen if the density of an object is less than the density of water?

Chemistry

1 answer:

Lelechka [254]3 years ago

4 0

Answer:

The object will float on the surface of water if its density is less than the equal volume of water.

Explanation:

Density:

It is define as mass per unit volume.

d=m/v

it is mostly measure in g/mL

it is represented by ρ (rho)

The density of water is one gram per cubic centimeter. If the object is less denser than water it will float. If the density of object is greater than the density of water it will sink.

Other examples:

some rocks are more denser then water so they will sink in it.

density of oil is less than vinegar, so it will float on the surface of vinegar

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3 years ago

What would happen if carbon -14 gained 1 proton and lost 1 neutron?

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3 years ago

Bradley was working in the lab. He accidentally poured a container of concentrated hydrochloric acid into his container of disti

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3 years ago

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A 1.2 L weather balloon on the ground has a temperature of 25°C and is at atmospheric pressure (1.0 atm). When it rises to an el

icang [17]

Answer:

The temperature of the air at this given elevation will be 53.32425°C

Explanation:

We can calculate the final temperature through the combined gas law. Therefore we will need to know 1 ) The initial volume, 2 ) The initial temperature, 3 ) Initial Pressure, 4 ) Final Volume, 5 ) Final Pressure.

Initial Volume = 1.2 L ; Initial Temperature = 25°C = 298.15 K ; Initial pressure = 1.0 atm ; Final Volume = 1.8 L ; Final pressure = 0.73 atm

We have all the information we need. Now let us substitute into the following formula, and solve for the final temperature ( T $_2$ ),

P $_1$ V $_1$ / T $_1$ = P $_2$ V $_2$ / T $_2$ ,

T $_2$ = P $_2$ V $_2$ T $_1$ / P $_1$ V $_1$ ,

T $_2$ = 0.73 atm $*$ 1.8 L $*$ 298.15 K / 1 atm $*$ 1.2 L = ( 0.73 $*$ 1.8 $*$ 298.15 / 1 $*$ 1.2 ) K = 326.47425 K,

T $_2$ = 326.47425 K = 53.32425 C

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3 years ago