Answer:
562.6
Explanation:
This is because in order to convert 5.626 liters to centileters, you have to multiply the volume value by 100.
Hope this helps!
Mass of iron(III)oxide, Fe2O3 sample = 1.143*10^2 g
Molar mass of Fe2O3 = 159.69 g/mole
i.e. 1 mole of Fe2O3 weighs 159.69 g
Based on stoichiometry:
1 mole of Fe2O3 has 2 moles of Fe
Atomic mass of Fe = 55.85 g/mole
Therefore we can write:
159.69 g of Fe2O3 is composed of 2*55.85 g of Fe
Thus, amount of Fe present in 1.143*10^2 g sample of Fe2O3 is
= 1.143*10^2 * 2* 55.85/159.69
= 7.995*10^-1 g
For this answer you could smell them and the 1 that almost made you pase out probably is putting off carbon manaxiod
I think the most suitable answer will be thermal energy
Answer:
Explanation:
Neutral atoms can be turned into positively charged ions by removing one or more electrons. A neutral sodium atom, for example, contains 11 protons and 11 electrons. By removing an electron from this atom we get a positively charged Na+ ion that has a net charge of +1.
