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3 years ago

What do acids feel like

Chemistry

1 answer:

djverab [1.8K]3 years ago

3 0

Answer:

In fact, some strong bases can burn the skin as badly as strong acids. Bases feel soapy or slippery because they react with acidic molecules in your skin called fatty acids. ... Like acids, bases change the colors of acid-base indicators, but the colors they produce are different. Bases turn litmus paper blue.

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If 76.4 grams of ammonium chloride are used, how many grams of water are

Ira Lisetskai [31]

Answer:

Explanation:

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3 years ago

The photoelectric effect occurs when _____ are emitted from metal when the metal is struck by light of certain frequencies.

Ainat [17]

Answer:

electrons

Explanation:

The photoelectric effect occurs when electrons are emitted from metal when the metal is struck by light of certain frequencies.

Some of the applications of this effect include photomultipliers (which are a key component in spectroscopy instruments) and night vision devices.

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3 years ago

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What is the kinetic energy of a ball with a mass of 0.5 kg and a velocity of 10 m/s? (Formula:) 25 J 5 J 50 J 100 JWhat is the k

nlexa [21]

Answer:

25J

Explanation:

K.E = 1/2mv^2

= 1/2*0.5*10^2

= 25J

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2 years ago

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The density of titanium is 4.51 g/cm^3. what is the volume (in cubic inches) of 3.5 lb of titanium?

Lina20 [59]

<span>(3.5 lb Ti) x (453.592 g Ti / 1 lb Ti) x (1 cm^3 Ti / 4.51 g Ti) x 0.0610237 in^3 / 1 cm^3) = 21 in^3 Ti. Use factor label method to cancel out units and make sure to cancel out the units to the solution, which in this case is volume of titanium in cubic inches. We only keep two digits because the original numbers use have two sig figs as the least amount when doing multiplication or division.</span>

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3 years ago

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A gas stream containing n-hexane in nitrogen with a relative saturation of 0.58 (as a fraction, multiply by 100% if you prefer %

kondor19780726 [428]

This problem is describing a gas mixture whose mole fraction of hexane in nitrogen is 0.58 and which is being fed to a condenser at 75 °C and 3.0 atm, obtaining a product at 3.0 atm and 20 °C, so that the removed heat from the system is required.

In this case, it is recommended to write the enthalpy for each substance as follows:

$H_{C-6}=y_{C-6}C_v(T_b-Ti)+\Delta _vH+C_v(T_f-Tb)\\\\H_{N_2}=y_{N_2}C_v(T_f-Ti)$

Whereas the specific heat of liquid and gaseous n-hexane are about 200 J/(mol*K) and 160 J/(mol*K) respectively, its condensation enthalpy is 31.5 kJ/mol, boiling point is 69 °C and the specific heat of gaseous nitrogen is about 29.1 J/(mol*K) according to the NIST data tables and $y_{C-6}$ and $y_{N_2}$ are the mole fractions in the gaseous mixture. Next, we proceed to the calculation of both heat terms as shown below:

$H_{C-6}=0.58*200(69-75)+(-31500)+160(20-69)=-40036J/mol\\\\H_{N_2}=0.42*29.1(20-75)=-672.21J/mol$

It is seen that the heat released by the nitrogen is neglectable in comparison to n-hexanes, however, a rigorous calculation is being presented. Then, we add the previously calculated enthalpies to compute the amount of heat that is removed by the condenser:

$Q=-40036+(-672.21)=-40708.21J$

Finally we convert this result to kJ:

$Q=-40708.21J*\frac{1kJ}{1000J}\\\\Q=-40.7kJ$

Learn more:

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2 years ago