Question

A person kicks a rock horizontally off a cliff with a speed of 35m/s. It takes 12 seconds to hit the ground below(don’t forget your units). What is the height of the cliff? What is the final vertical velocity? What is the range?

Answer 1

take gravity g as 9.81

height of cliff = ut +1/2at^2 = 1/2*(9.81)*12^2 = 706.32 meters

What is the final vertical velocity

v=u+at, final velocity v = 0 + 9.81*12 = 117.72 m/s