What potential difference would an electron have to fall through to acquire a speed of 3.00*10^6 m/sec?
1 answer:
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Answer:
(a) E= 3.36×10−2 V +( 3.30×10−4 V/s3 )t3
(b)
Explanation:
Given:
- radius if the coil,
- no. of turns in the coil,
- variation of the magnetic field in the coil,
- resistor connected to the coil,
(a)
we know, according to Faraday's Law:
where:
change in associated magnetic flux
where:
A= area enclosed by the coil
Here
So, emf:
(b)
Given:
Now, emf at given time:
∴Current