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aleksandr82 [10.1K]
4 years ago
6

What potential difference would an electron have to fall through to acquire a speed of 3.00*10^6 m/sec?

Physics
1 answer:
kirill [66]4 years ago
4 0

Answer:

25.6 V

Explanation:

The kinetic energy of electron associated with its potential difference is given by eV which is equal to the 1/2 mv^2.

m = 9.1 x 10^-31 kg, v = 3 x 10^6 m/s, e = 1.6 x 10^-19 C

eV = 1/2 m v^2

V = mv^2 / 2 e

V = (9.1 x 10^-31) x (3 x 10^6)^2 / (2 x 1.6 x 10^-19)

V = 25.6 V

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What should you do if your boat capsizes answers?
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6 0
3 years ago
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3 years ago
9. A 227 kg object is moved a distance of 2.4 m forward by a force. If 686 J of work is done on the object, what is the object’s
Korolek [52]

<em>1</em><em>.</em><em>259ms^2</em>

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since, WORK DONE = FORCE*DISTANCE

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3 years ago
Two small plastic spheres each have a mass of 1.1 g and a charge of -50.0 nC . They are placed 2.1 cm apart (center to center).
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Answer:

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F = 0.051 N

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Part b)

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3 0
3 years ago
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