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Mashcka [7]
3 years ago
8

An electric motor rotating a workshop grinding wheel at 1.06 102 rev/min is switched off. Assume the wheel has a constant negati

ve angular acceleration of magnitude 2.10 rad/s2. (a) How long does it take the grinding wheel to stop
Physics
1 answer:
kvasek [131]3 years ago
6 0

Answer:

t = 106π / 30*2.1

Explanation:

w_{i} = 1.06*10^{2}    => 106

    => 106 x 2π/60

    => 106/30π

∝ = -2.1 rad/sec²

w_{f} => 0

w_{f} = w_{i} + ∝t

∴ (w_{f} - w_{i}) / ∝ = t

t = 106π / 30*2.1

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When using a cell phone, a(n) ________ converter chip changes your voice's sound waves into digital signals.
Nuetrik [128]

Answer: analog-to-digital

Explanation: Analog-to-digital converters as the name implies simply refers to components which are used to convert continuous analog signals into a discrete analog outputs so they it can be read and processed by a microprocessor. The microprocessors are unable to depict and read analog signals which could be gathered from sound, light or water wave sources. This wave sources are then sampled, processed and sorted into levels by the analog-to-digital converter before being sent to the microprocessor so that the waves can be read.

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2 years ago
What is the relationship between mass and weight in physics?
Alex_Xolod [135]

We are aware that weight is the product of applied gravitational force and mass. W = MG thus, where W represents the weight, M the mass, and G the gravitational force. As a result, it might also mean that "an object's weight is directly proportionate to its mass."

<h3>What is mass?</h3>
  • Mass is a physical body's total amount of matter.
  • It also serves as a gauge for the body's inertia, or resistance to acceleration (change in velocity) in the presence of a net force.
  • The strength of an object's gravitational pull to other bodies is also influenced by its mass.
  • The kilogram is the primary mass unit in the SI (kg).
  • Even though weight is frequently measured using a spring scale rather than a balancing scale and directly compared with known masses, mass is not the same as weight in physics.
<h3>What is weight?</h3>
  • The force exerted on an object by gravity is known as the weight of the object in science and engineering.
  • Weight is sometimes described as a vector quantity, or the gravitational force exerted on the object, in some common textbooks.
  • Others define weight as a scalar quantity, the gravitational force's strength.
  • Others define it as the strength of the force applied to a body as a result of systems designed to resist the effects of gravity; the weight is the amount that is determined, for instance, by a spring scale.

Learn more about mass here:

brainly.com/question/19694949

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7 0
1 year ago
State keplers law........​
S_A_V [24]

Answer:

There are actually three, Kepler's laws that is, of planetary motion: 1) every planet's orbit is an ellipse with the Sun at a focus; 2) a line joining the Sun and a planet sweeps out equal areas in equal times; and 3) the square of a planet's orbital period is proportional to the cube of the semi-major axis of its

4 0
2 years ago
(1 pt) A bucket of water of mass 20 kg is pulled at constant velocity up to a platform 35 meters above the ground. This takes 14
Elenna [48]

Answer:

w = 5832.372 Joules

Explanation:

Mass of water, m = 20 kg

The water was pulled up to a height of 35 meters, i.e. h = 35 m

It takes 14 minutes to pull up the water through the height, 35 m

speed = distance/ time = 35/14 = 2.5 m/min

The bucket's height, y = speed * time = 2.5t meters

6 kg of water drips out of the bucket throughout the 14 minutes

The rate at which the water drips drips out = (6/14) = 0.4286 kg/min

Mass of water that drips out in time, t = 0.4286t kg

The mass of water remaining = (20 - 0.4286t) kg

Change in Workdone, Δw = mgΔy

Δy = 2.5 Δt

Δw = mg *  2.5 Δt

dw =  (20 - 0.4286t)g2.5 dt

integrating both sides

dw = (50g - 1.07gt)dt

w = \int\limits^a_b {(50g-1.07gt)} \, dx where b = 0, a = 14

w = 50gt - 1.07g(t²)/2      g = 9.8 m/s²

w = 490t - 5.243t²

w = (490*14 - 5.243*14²) - (490*0 - 5.243*0²)

w = 6860 - 1027.628

w = 5832.372 Joules

3 0
3 years ago
Suppose a straight 1.00-mm-diameter copper wire could just "float" horizontally in air because of the force due to the Earth’s m
insens350 [35]

To solve this problem it is necessary to apply the concepts related to the Force since Newton's second law, as well as the concept of Electromagnetic Force. The relationship of the two equations will allow us to find the magnetic field through the geometric relations of density and volume.

F_{mag}= BIL

Where,

B = Magnetic Field

I = Current

L = Length

<em>Note: F_{mag}  is a direct adaptation of the vector relation F=q \times V \times B</em>

From Newton's second law we know that the relation of Strength and weight is determined as

F_g = mg

Where,

m = Mass

g = Gravitational Acceleration

For there to be balance the two forces must be equal therefore

F_{mag} = F_g

BIL = mg

Our values are given as,

Diameter (d) = 1.0mm = 1*10^{-3}m

Radius (r) = \frac{d}{2} = \frac{1*10^{-3}}{2} = 0.5*10^{-3}m

Magnetic Field (B) = 5.0*10^{-5} T

From the relationship of density another way of expressing mass would be

\rho = \frac{m}{V} \rightarrow m = \rho V

At the same time the volume ratio for a cylinder (the shape of the wire) would be

V = \pi r^2 L \rightarrow L =Length, r= Radius

Replacing this two expression at our first equation we have that:

BIL = mg

BIL = ( \rho V)g

BIL = ( \rho \pi r^2 L)g

Re-arrange to find I

I = \frac{( \rho \pi r^2 L)g}{BL}

I = \frac{( \rho \pi r^2 )g}{B}

We have for definition that the Density of copper is 8.9*10^3 Kg/m^3, gravity acceleration is 9.8m/s^2 and the values of magnetic field (B) and the radius were previously given, then:

I = \frac{( (8.9*10^3 ) \pi (0.5*10^{-3})^2 )(9.8)}{5.0*10^{-5}}

I = 1370.05A

The current is too high to be transported which would make the case not feasible.

8 0
2 years ago
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