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horrorfan [7]
3 years ago
10

Considering the factors that affect gravitational pull, in which location would the gravitational pull from the earth be SMALLES

T on you? * 2 points A) visiting friends at the beach B) visiting Santa on the second floor of the mall C) visiting Uncle Chrissy in the Himalayan Mountains D) visiting cousin Snelfu in his submarine at the bottom of the ocean
Physics
1 answer:
OleMash [197]3 years ago
4 0
C. The higher the altitude the less gravity affects you
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A spiral staircase in a building is in the shape of a helix of radius 5 meters. Between two oors of the building, the stairs mak
Vitek1552 [10]

Answer:

2744Nm

Explanation:

The gravitational field is conservative. The gravitational force only acts on a vertical direction. Hence, independently of the form of the trajectory, the work done by the gravity against the person demands the calculation of the integral of the force multiplied by the vertical displacement of the person:

W_g=\int_0^{4}Mgdz=Mg[4]=(70kg)(9.8\frac{m}{s^2})(4m)=2744Nm

where we have taken that the displacement of the person h=z and df=dz.

hope this helps!!

5 0
3 years ago
A 25N force is applied to a bar that can pivot around its end. The force is r=0.75 m away from the end of an angle at 0= 30. wha
Alecsey [184]

Answer:

<h2>9.375Nm</h2>

Explanation:

The formula for calculating torque τ = Frsin∅ where;

F = applied force (in newton)

r = radius (in metres)

∅ = angle that the force made with the bar.

Given  F= 25N, r = 0.75m and ∅ = 30°

torque on the bar τ  = 25*0.75*sin30°

τ = 25*0.75*0.5

τ = 9.375Nm

The torque on the bar is 9.375Nm

6 0
4 years ago
2. A 2000 kg car with speed 12.0 m/s hits a tree. The tree does not move or
krek1111 [17]

a) The work done by the tree is -1.44\cdot 10^5 J

b) The amount of force applied is 2880 N

Explanation:

a)

According to the work-energy theorem, the work done on the car is equal to the change in kinetic energy of the car. Therefore, we can write:

W=K_f - K_i = \frac{1}{2}mv^2 - \frac{1}{2}mu^2

where

W is the work done on the car

m is the mass of the car

u is its initial speed

v is its final speed

For the car in this problem, we have:

m = 2000 kg

u = 12.0 m/s

v = 0 (since the car comes to a stop, after the crash)

Therefore, the work done by the tree on the car is:

W=0-\frac{1}{2}(2000)(12.0)^2=-1.44\cdot 10^5 J

The work is negative because it is done in the direction opposite to the direction of motion of the car.

b)

The work done by the tree on the car can also be rewritten as

W=Fd

where

F is the force applied on the car

d is the displacement of the car during the collision

In this situation, we have:

W=-1.44\cdot 10^5 J is the work done

d=50.0 cm = 0.50 m is the displacement of the car during the collision

Solving the equation for F, we find the force exerted by the tree on the car:

F=\frac{W}{d}=\frac{-1.44\cdot 10^5 J}{0.50}=-2880 N

Where the negative sign means the force is applied opposite to the direction of motion of the car. Therefore, the magnitude of the force applied is 2880 N.

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

3 0
4 years ago
The majority of sediments in the ocean are found...
makkiz [27]
I'm in middle school, but I think I know the answer, I am sorry if I am wrong.

It's D
6 0
4 years ago
Good afternoon.....from bangladesh....
Step2247 [10]

Answer:

good afternoon

Explanation:

4 0
3 years ago
Read 2 more answers
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