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jok3333 [9.3K]
3 years ago
9

A planet has two moons, Moon A and Moon B, that orbit at different distances from the planet's center, as shown. Astronomerscoll

ect data regarding the planet, the two moons, and their obits. The astronomers are able to estimate the planet's radius and
mass.
The masses of the two moons are determined to be 2M for Moon A and M for Moon B. It is observed that the distance
between Moon B and the planet is two times that of the distance between Moon A and the planet. How does force exerted from
the planet on Moon A compare to the force exerted from the planet on Moon B?




READ CAREFULLY PLEASE


A) The gravitational force exerted from the planet on Moon A is two times larger than the gravitational force exerted from the planet on Moon B

B) The gravitational force exerted from the planet on Moon A is eight times larger than the gravitational force exerted from the planet on Moon B

C) The gravitational force exerted from the planet on Moon A is two times smaller than the gravitational force exerted from the planet on Moon B

D) The gravitational force exerted from the planet on Moon A is eight times smaller than the gravitational force exerted from the planet on Moon B
​
Physics
2 answers:
Crazy boy [7]3 years ago
8 0

B) The gravitational force exerted from the planet on Moon A is eight times larger than the gravitational force exerted from the planet on Moon B

Gala2k [10]3 years ago
5 0
C: The gravitational force exerted from the planet on Moon A is two times smaller than the gravitational force exerted from the planet on Moon B.
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explain why when someone uses his thumb to push a pin into a block of wood the pressure on the wood is greater than the pressure
Charra [1.4K]

Answer:

the smaller the area the bigger the pressure

8 0
3 years ago
Read 2 more answers
6. A car, 1110 kg, is traveling down a horizontal road at 20.0 m/s when it locks up its brakes. The coefficient of friction betw
USPshnik [31]

Answer:

x=22.65m

Explanation:

We have an uniformly accelerated motion, with a negative acceleration. Thus, we use the kinematic equations to calculate the distance will it take to bring the car to a stop:

v_f^2=v_0^2-2ax\\\frac{0^2-v_0^2}{-2a}=x\\x=\frac{v_0^2}{2a}

The acceleration can be calculated using Newton's second law:

\sum F_x:F_f=ma\\\sum F_y:N=mg

Recall that the maximum force of friction is defined as F_f=\mu N. So, replacing this:

\mu N=ma\\\mu mg=ma\\a=\mu g\\a=0.901(9.8\frac{m}{s^2})\\a=8.83\frac{m}{s^2}

Now, we calculate the distance:

x=\frac{v_0^2}{2a}\\x=\frac{(20\frac{m}{s})^2}{2(8.83\frac{m}{s^2})}\\x=22.65m

7 0
3 years ago
Students are experimenting with circuits in their physics class and they build the two working circuits pictured below. The batt
bija089 [108]

The complete observation about adding bulb 3 is the brightness of the bulbs has to do with power which considers both the voltage and the current: less voltage x less current = dimmer bulbs.  In circuit A, the voltage is divided across the resistors and the current decreases as resistance increases.  In circuit B, the voltage is the same in each parallel section of the circuit and the current through that section of the circuit only depends on the resistor in that section.

<h3>What is power of the circuit?</h3>

The power of the bulb or any resistor is equal to the product of voltage and  current flowing through it.

P = VI

Circuit A has bulbs in series while the circuit B has bulbs in parallel.

When bulb 3 added to circuit A,  the brightness of all the bulbs dimmed but when bulb 3 (R3) added to circuit B, nothing changed in the brightness of the bulb.

The brightness is depended on the power of the circuit. When both the voltage and current are less, the bulb will be dimmed. In circuit A, series resistors divide the voltage across them. In circuit B, voltage is equal for all the resistors.

Thus, the last option is correct.

Learn more about power.

brainly.com/question/2933971

#SPJ1

4 0
2 years ago
Suppose that placing 0.3 inch of lead in front of a gamma source reduces the count rate from 1045 cps to 573 cps. What is um^-1
Ainat [17]

Answer:

14.49 g/cm²

Explanation:

I = Io e^-(ux)

Where:

I = 573

Io = 1045

x = 0.3 inches and

rho = 11.4g/cm^3

Using the conversion constant

1 inch = 2.54 cm;

0.3 inches = 0.3 * 2.54 cm

0.3 inches = 0.762 cm

I/Io = e^-(ux), or say

Io/I = e^(ux), taking the In of both sides

ln(Io/I) = ux, making u subject of formula

u = 1/x * ln(Io/I)

u = 1/0.762 * ln(1045/573)

u = 1.312 * 0.6

u = 0.787

Next, we say that

u/rho = 0.7872/11.4 = 0.069

And finally, we make

1/(u/rho) to be our final answer

Inverse of the answer is = 14.49 g/cm²

Therefore, the um^-1 in g/cm^2? is 14.49

5 0
2 years ago
The change in electric potential energy per unit charge is
zepelin [54]

A) amperes

B) current.  

C) gravity.  

D) voltage.

correct. D) Voltage is the change in electric potential energy per unit charge. It is sometimes called the electric potential difference

6 0
3 years ago
Read 2 more answers
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