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4 years ago

12

a student sees a newspaper ad for an apartment that has 1330 square foot of floor space. how many square meters of area are ther

e?

1 answer:

djverab [1.8K]4 years ago

4 0

There are 3.3 feet in 1 meter, and 0.3 meters in 1 foot
123.561 square meters

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A vertical bar magnet is dropped through the center of a horizontal loop of wire, with its north pole leading. At the instant wh

AlladinOne [14]

Answer:

The induced current will be counterclockwise.

Explanation:

Magnetic field lines always begin on north poles and end on south poles. This means that there is an increase of magnetic field lines going into the plane of the loop. The induced current will be counterclockwise to oppose this change.

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4 years ago

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A car is traveling at 20 m/s. It takes the car 120s to go from one intersection to a second. What was the displacement of the ca

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We don't know if the road is perfectly straight between the intersections, or if the road bends, curves, or turns between them. So we don't have enough information to calculate the displacement between them.

But we <em>can</em> calculate the <u>distance</u> the car traveled between them.

Distance = (speed) (time)

Distance = (20 m/s) (120 s)

<em>Distance = 2,400 meters</em>

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3 years ago

What type of machine is a seesaw?

AfilCa [17]

A.simple machine hpoe u get it

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3 years ago

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Please do parts (a) and part (b) below and include diagrams where applicable:

Harlamova29_29 [7]

Answer:

Part a)

m = 232.1 gram

Part b)

M = 928.6 gram

Explanation:

Part a)

As we know that frequency of vibration for a given spring block system is given by formula

$f = \frac{1}{2\pi}\sqrt{\frac{k}{m}}$

so if it is given as 0.90 Hz then we will have

$0.90Hz = \frac{1}{2\pi}\sqrt{\frac{k}{m}}$

Now if additional mass is attached with it the frequency changed to 0.50 Hz

$0.50 Hz = \frac{1}{2\pi}\sqrt{\frac{k}{m + 520}}$

now divide two equations

$\frac{0.90}{0.50} = \sqrt{\frac{m + 520}{m}}$

$3.24m = m + 520$

$m = 232.1 g$

Part b)

Now the frequency is changed to 0.45 Hz

so again we will have

$0.45 Hz = \frac{1}{2\pi}\sqrt{\frac{k}{M}}$

again divide it with first equation above

$\frac{0.90}{0.45} = \sqrt{\frac{M}{m}}$

as we know that m = 232.1 g

so total mass needed for 0.45 Hz will be

$M = 928.6 gram$

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3 years ago

two pendula are released from rest at the same height h above their lowest points. how do the maximum velocities of the two pend

Alika [10]

The simple pendulum concept and rotational kinematics relationships allow finding the result for the velocity relationship

The shortest pendulum (w₁) has more speed than the longest pendulum (w₂)

w₁ = $\sqrt{2}$ w₂

The simple harmonic movement is a periodic movement where the restoring force is proportional to the elongation, in the case of the simple pendulum it is fulfilled for angles less than 10º. The expression for motion is

θ = θ₀ cos ωt

ω² = g / l

the angular velocity is defined by

w = $\frac{d \theta}{dt}$

w = - θ₀ ω sin ωt

Where θ₀ is the initial angle or amplitude, w is the angular velocity, t the time, g the acceleration of gravity and l the length of the pendulum

Let's find the angular velocity for each pendulum

ω ₁ = $\sqrt{ \frac{g}{l_1} }$

Indicate that the second pendulum length is

l₂ = 2 l₁

ω₂ = $\sqrt{\frac{g}{2l_1} }$

the pendulum speed is maximum at the lowest point of the trajectory that occurs when the sine function has its maximum value

w = θ₀ω

Suppose that the two pendulums are released with the same initial angle

Pendulum 1

w₁ = θ₀ $\sqrt{\frac{g}{l_1} }$

Pendulum 2

w₂ = θ₀ $\sqrt{\frac{g}{2l_1} }$

We look for the relationship between the two speeds

$\frac{w_1}{w_2} = \sqrt{2}$

In conclusion, using the simple pendulum concept and the rotational kinematics relations we can find the result for the velocity relation

The shortest pendulum (w₁) has more speed than the longest pendulum (w₂)

w₁ = √2 w₂

Learn more here: brainly.com/question/24159297

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3 years ago