B.
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Mdmdkkdkdskksksk
Answer:
= -457.9 kJ and reaction is product favored.
Explanation:
The given reaction is associated with 2 moles of ![NH_{3}](https://tex.z-dn.net/?f=NH_%7B3%7D)
Standard free energy change of the reaction (
) is given as:
, where T represents temperature in kelvin scale
So, ![\Delta G^{0}=(-683.1\times 10^{3})J-(273K\times -365.6J/K)=-583291.2J](https://tex.z-dn.net/?f=%5CDelta%20G%5E%7B0%7D%3D%28-683.1%5Ctimes%2010%5E%7B3%7D%29J-%28273K%5Ctimes%20-365.6J%2FK%29%3D-583291.2J)
So, for the reaction of 1.57 moles of
, ![\Delta G^{0}=(\frac{1.57}{2})\times -583291.2J=-457883.592J=-457.9kJ](https://tex.z-dn.net/?f=%5CDelta%20G%5E%7B0%7D%3D%28%5Cfrac%7B1.57%7D%7B2%7D%29%5Ctimes%20-583291.2J%3D-457883.592J%3D-457.9kJ)
As,
is negative therefore reaction is product favored under standard condition.
Answer:
From molar mass=total RAM of each individual element
78.8=(16+1)×3+M
78.8-51=M
27.8g/mol=M
<h3>
Answer:</h3>
9 mol H₂O
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Moles
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
- Analyzing reactions RxN
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Balanced] 6H₂ + O₂ → 3H₂O
[Given] 18 mol H₂
[Solve] mol H₂O
<u>Step 2: Identify Conversions</u>
[RxN] 6 mol H₂ → 3 mol H₂O
<u>Step 3: Stoich</u>
- [DA] Set up conversion:
![\displaystyle 18 \ mol \ H_2(\frac{3 \ mol \ H_2O}{6 \ mol \ H_2})](https://tex.z-dn.net/?f=%5Cdisplaystyle%2018%20%5C%20mol%20%5C%20H_2%28%5Cfrac%7B3%20%5C%20mol%20%5C%20H_2O%7D%7B6%20%5C%20mol%20%5C%20H_2%7D%29)
- [DA] Simplify:
![\displaystyle 18 \ mol \ H_2(\frac{1 \ mol \ H_2O}{2 \ mol \ H_2})](https://tex.z-dn.net/?f=%5Cdisplaystyle%2018%20%5C%20mol%20%5C%20H_2%28%5Cfrac%7B1%20%5C%20mol%20%5C%20H_2O%7D%7B2%20%5C%20mol%20%5C%20H_2%7D%29)
- [DA] Divide [Cancel out units]:
![\displaystyle 9 \ mol \ H_2O](https://tex.z-dn.net/?f=%5Cdisplaystyle%209%20%5C%20mol%20%5C%20H_2O)
Answer: im in 8th they got me doin this
Explanation: i need help quick