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E = mc^2
<span>where E is the energy in joules, </span>
<span>m is the mass in kilograms, </span>
<span>and c is the speed of light. </span>
<span>E = mc^2 </span>
<span>E = (5.63 x 10^-7 kg)(3 x 10^8 m/s)^2 </span>
<span>E = 5.07 x 10^10 J </span>
The correct answer is <span>B. A fuse is used to break a circuit when there is too much current.
I hope this helps :)
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For a reaction rate that increases by a factor of 655 in the presence of a catalyst at 37°C, the activation energy of the new pathway is mathematically given as
Ea2=89.28JKoule/mol
<h3>What is the activation energy of the new pathway, all other factors being equal?</h3>
Generally, the equation for the rate constant is mathematically given as
K=Ae^{Ea1/Rt}
Therefore

Ea2=89286.083Joule/mol
In conclusion, the activation energy
Ea2=89.28JKoule/mol
Read more about Energy
brainly.com/question/13439286
Units of measurement should be shown on the x axis.