The reaction of Na2CrO4 (aq) and AgNO3 (aq) is as follows:
2AgNO3 (aq) +Na2CrO4 (aq) ⇒Ag2CrO4 (s) + 2NaNO3 (aq).
During this reaction, part of the CrO42- reacts with Ag+ and precipitates out of the solution, part of the CrO42- (excess amount) remains in the solution.
To find out how much CrO42- is reacted:
Moles of initial CrO42- = 0.075 L * 2.5 M = 0.1875 mole
Moles of initial Ag+ = 0.125 L * 1.79 M = 0.2238 mole
The reaction ratio between CrO42- and Ag+ is 1:2 according to the equation. So moles of CrO42- that is reacted is 0.2238 mole/2 = 0.1119 mole. Therefore, moles of CrO42- that remains in the solution is 0.1875mole-0.1119mole = 0.0756 mole
So the final concentration of CrO42- in the solution is 0.0756mole/(0.075L+0.125L)= 0.378 M.
Rate of Effusion of Unknown gas = rX = 0.5
Rate of Effusion of Hydrogen = rH = 1
M.mass of Hydrogen = mH = 2 g/mol
M.mass of Unknown gas = mX = ?
Formula used:
rH / rX = √mX / mH
taking square on both sides,
r²H / r²X = mX / mH
Solving for mX,
mX = (r²H ÷ r²X) × mH
Putting values,
mX = [1² ÷ (0.5)²] × 2 g/mol
mX = (1 ÷ 0.25) × 2 g/mol
mX = 4 × 2 g/mol
mX = 8 g/mol
Result:
Molecular Mass of Unknown gas is 8 g/mol.
According to markovnikov's rule of the electrophilic addition to an alkene, the electrophile, usually a proton, is more likely to add to the less-substituted carbon in a double bond.
With additional substituents present in this configuration, the intermediate carbocation is stabilised by being located on the more-substituted carbon.
The nucleophile will then end up in a double bond on the more-substituted carbon in a reaction that follows Markovnikov's rule.The outcome of some addition reactions is described by Markovnikov's rule or Markownikoff's rule in organic chemistry. Vladimir Markovnikov, a Russian scientist, created the rule in 1870.
To learn more about Markovnikov's rule
brainly.com/question/14529644
#SPJ4
False, fossil fuels and stuff like that contributes to the presence of greenhouse gases.
Density = mass/volume = 316/22.5 = 14.045g/mL.