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Svetlanka [38]
3 years ago
7

What is the value expression below 43-13+105\(3x5)

Mathematics
1 answer:
Zarrin [17]3 years ago
7 0
43-13+\dfrac{105}{3\times5}=30+\dfrac{105}{15}=30+7=37
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Answer:

2 (B)

Step-by-step explanation:

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3 years ago
An electric current, I, in amps, is given by I=cos(wt)+√8sin(wt), where w≠0 is a constant. What are the maximum and minimum valu
exis [7]
Take the derivative with respect to t
- w \sin(wt) + \sqrt{8} w cos(wt)
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
0 = -w \sin(wt) + \sqrt{8} w cos(wt)
divide by w
0 =- \sin(wt) + \sqrt{8} cos(wt)
we add sin(wt) to both sides

\sin(wt)= \sqrt{8} cos(wt)
divide both sides by cos(wt)
\frac{sin(wt)}{cos(wt)}= \sqrt{8}   \\  \\ arctan(tan(wt))=arctan( \sqrt{8} ) \\  \\ wt=arctan(2 \sqrt{2)} OR\\ wt=arctan( { \frac{1}{ \sqrt{2} } )
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(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

I=cos(2n \pi -2arctan( \sqrt{2} ))
since 2npi is just the period of cos
cos(2arctan( \sqrt{2} ))= \frac{-1}{3} 

substituting our second soultion we get
I=cos(2n \pi +2arctan( \frac{1}{ \sqrt{2} } ))
since 2npi is the period
I=cos(2arctan( \frac{1}{ \sqrt{2}} ))= \frac{1}{3}
so the maximum value =\frac{1}{3}
minimum value =- \frac{1}{3}


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3 years ago
A sum of money is divided into the ratio 3:4. The larger portion is then divided into 3 parts in
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Step-by-step explanation:

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Answer:

x ≈ 3.1 ft

Step-by-step explanation:

The segment from the centre to the chord is a perpendicular bisector, thus

The triangle is right with base = \frac{1}{2} x

Applying Pythagoras' identity to the right triangle, then

(\frac{1}{2} x )² + 1.4² = 2.1²

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3 years ago
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