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alex41 [277]
4 years ago
9

Counting Atoms in Compound 1. 4K2CO3 K=___ C=___ O=___

Chemistry
2 answers:
VARVARA [1.3K]4 years ago
8 0
K= 8
C=4
O= 12

The number after the letter shows how much of that atom there is.

The 4 shows there is 4 of each after it, so 4 of the K2, C, and O3. You would want to multiply the K2, C, and O3 by 4.
horsena [70]4 years ago
3 0

Answer:

K = 8, C = 1, O = 12

Explanation:

This question has to do with the atomicity of each atom in the compound. Atomicity is the total number of atoms that constitute a molecule.

In 4 moles of potassium carbonate (K₂CO₃), we have

K = 4 moles ₓ 2 atoms = 8 atoms

C = 4 moles ₓ 1 atom = 4 atoms

O = 4 moles ₓ 3 atoms = 12 atoms

NOTE: The "4" before the molecule signifies the number of moles (molecules) of K₂CO₃ which means it "affects" each of the atom that makes up the compound.

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3 years ago
A solution of NaOH has a concentration of 25.00% by mass. What mass of NaOH is present in 0.250 g of this solution? Use the peri
tekilochka [14]

Answer:

1) 0.0625  g.

2) 0.0125 g.

Explanation:

<em>1) A solution of NaOH has a concentration of 25.00% by mass. What mass of NaOH is present in 0.250 g of this solution?</em>

  • We can use the relation:

mass% of NaOH = [(mass of NaOH)/(mass of solution)] x 100.

mass% of NaOH = 25.0%, mass of NaOH = ???  g, mass of solution = 0.250 g.

∴ mass of NaOH = (mass% of NaOH)(mass of solution)/100 = (25.0%)(0.250 g)/100 = 0.0625  g.

<em>2) What mass of NaOH must be added to the solution to increase the concentration to 30.00% by mass?</em>

We can use the relation:

mass% of NaOH = [(mass of NaOH)/(mass of solution)] x 100.

mass% of NaOH = 30.0%, mass of NaOH = ???  g, mass of solution = 0.250 g.

∴ mass of NaOH = (mass% of NaOH)(mass of solution)/100 = (30.0%)(0.250 g)/100 = 0.075  g.

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9 0
4 years ago
Read 2 more answers
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Answer:

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Hope I helped!

Best regards!!

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