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alex41 [277]
4 years ago
9

Counting Atoms in Compound 1. 4K2CO3 K=___ C=___ O=___

Chemistry
2 answers:
VARVARA [1.3K]4 years ago
8 0
K= 8
C=4
O= 12

The number after the letter shows how much of that atom there is.

The 4 shows there is 4 of each after it, so 4 of the K2, C, and O3. You would want to multiply the K2, C, and O3 by 4.
horsena [70]4 years ago
3 0

Answer:

K = 8, C = 1, O = 12

Explanation:

This question has to do with the atomicity of each atom in the compound. Atomicity is the total number of atoms that constitute a molecule.

In 4 moles of potassium carbonate (K₂CO₃), we have

K = 4 moles ₓ 2 atoms = 8 atoms

C = 4 moles ₓ 1 atom = 4 atoms

O = 4 moles ₓ 3 atoms = 12 atoms

NOTE: The "4" before the molecule signifies the number of moles (molecules) of K₂CO₃ which means it "affects" each of the atom that makes up the compound.

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3 years ago
Given the balanced equation representing a reaction: 2h2o(l) + 571.6 kJ -> 2h2(g) + o2(g). What occurred as a result of this
Ivan

Answer: option D) energy was absorbed and entropy increased.


Explanation:


1) Given balanced equation:


2H₂O (l) + 571.6 kJ → 2 H₂ (g) + O₂(g).


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7 0
4 years ago
The scattering of light by a colloid is called the Brownian lighting, Tyndall effect, colloidal scattering, or aggregate reflect
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3 0
3 years ago
Read 2 more answers
How many moles would be in 85.OmL of 0.750M KOH?
Harlamova29_29 [7]

Answer: There are 0.0637 moles present in 85.0 mL of 0.750 M KOH.

Explanation:

Given: Volume = 85.0 mL (1 mL = 0.001 L) = 0.085 L

Molarity = 0.750 M

It is known that molarity is the number of moles of solute present in liter of a solution.

Therefore, moles present in given solution are calculated as follows.

Molarity = \frac{moles}{Volume (in L)}\\0.750 M = \frac{moles}{0.085 L}\\moles = 0.0637 mol

Thus, we can conclude that there are 0.0637 moles present in 85.0 mL of 0.750 M KOH.

7 0
3 years ago
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