Answer:
454.3 g.
Explanation:
1.0 mol of CaO liberates → – 64.8 kJ.
??? mol of CaO liberates → - 525 kJ.
∴ The no. of moles needed = (1.0 mol)(- 525 kJ)/(- 64.8 kJ) = 8.1 mol.
<em>∴ The no. of grams of CaO needed = no. of moles x molar mass</em> = (8.1 mol)(56.077 g/mol) = <em>454.3 g.</em>
Answer: The amount of water formed is 12 moles
Explanation: Please see the attachments below
Atomic Number of Zinc is 30, means it contains 30 electrons. So, its electronic configuration is as follow,
1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰
As,
1s², 2s², 2p⁶, 3s², 3p⁶ = Argon
So,
Electronic configuration of Zinc in shorthand notation is as follow,
[Ar] 4s², 3d¹⁰
I cannot see your question to help you... sorry
