Almost all catalysts work by lowering the activation energy of the reaction with no change in the free energy of the reaction
- So in this case we can say that palladium reduce automobile pollution by catalyzing the reaction between un-burned hydrocarbons and oxygen :
D. by decreasing the activation energy
Answer:
(A) endothermic
(A) Yes, absorbed
Explanation:
Let's consider the following thermochemical equation.
2 Fe₂O₃(s) ⇒ 4 FeO(s) + O₂(g) ΔH = 560 kJ
Since ΔH > 0, the reaction is endothermic.
We can establish the following relations:
- 560 kJ are absorbed when 2 moles of Fe₂O₃ react.
- The molar mass of Fe₂O₃ is 160 g/mol.
Suppose 66.6 g of Fe₂O₃ react. The heat absorbed is:

Answer: Dalton's atomic theory proposed that all matter was composed of atoms, indivisible and indestructible building blocks. While all atoms of an element were identical, different elements had atoms of differing size and mass. ==INFORMATION IS FROM Google NOT MY CONTENT!!!== Your fellow Brainly user, GalaxyGamingKitty
evaporation brings water "skywards"
Answer:
The rate at which
is being produced is 0.0228 M/s.
The rate at which
is being consumed is 0.0912 M/s.
Explanation:

Rate of the reaction : R
![R=\frac{-1}{4}\frac{d[PH_3]}{dt}=\frac{1}{6}\frac{d[H_2]}{dt}=\frac{1}{1}\frac{d[P_4]}{dt}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B-1%7D%7B4%7D%5Cfrac%7Bd%5BPH_3%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B6%7D%5Cfrac%7Bd%5BH_2%5D%7D%7Bdt%7D%3D%5Cfrac%7B1%7D%7B1%7D%5Cfrac%7Bd%5BP_4%5D%7D%7Bdt%7D)
The rate at which hydrogen is being formed = ![\frac{d[H_2]}{dt}=0.137 M/s](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BH_2%5D%7D%7Bdt%7D%3D0.137%20M%2Fs)
![R=\frac{1}{6}\frac{d[H_2]}{dt}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B1%7D%7B6%7D%5Cfrac%7Bd%5BH_2%5D%7D%7Bdt%7D)

The rate at which
is being produced:
![R=\frac{1}{1}\frac{d[P_4]}{dt}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B1%7D%7B1%7D%5Cfrac%7Bd%5BP_4%5D%7D%7Bdt%7D)
![0.0228 M/s=\frac{1}{1}\frac{d[P_4]}{dt}](https://tex.z-dn.net/?f=0.0228%20M%2Fs%3D%5Cfrac%7B1%7D%7B1%7D%5Cfrac%7Bd%5BP_4%5D%7D%7Bdt%7D)
The rate at which
is being consumed :
![R=\frac{-1}{4}\frac{d[PH_3]}{dt}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B-1%7D%7B4%7D%5Cfrac%7Bd%5BPH_3%5D%7D%7Bdt%7D)
![0.0228 M/s\times 4=\frac{-1}{1}\frac{d[PH_3]}{dt}](https://tex.z-dn.net/?f=0.0228%20M%2Fs%5Ctimes%204%3D%5Cfrac%7B-1%7D%7B1%7D%5Cfrac%7Bd%5BPH_3%5D%7D%7Bdt%7D)
![\frac{-1}{1}\frac{d[PH_3]}{dt}=0.912 M/s](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B1%7D%5Cfrac%7Bd%5BPH_3%5D%7D%7Bdt%7D%3D0.912%20M%2Fs)