Ask question

Ask question

All categories

AleksandrR [38]

3 years ago

13

Polygon ABCD is translated to create polygon A′B′C′D′. Point A is located at (1, 5), and point A′ is located at (-2, 1). What is

the distance from B to B′ ?

1 answer:

wolverine [178]3 years ago

6 0

Distance formula = sqrt[(x1 - x2)^2 + (y2-y1)^2]
D = sqrt[(1 + 2)^2 + (5 - 1)^2]
D = sqrt[3^2 + 4^2]
D = sqrt(9 + 16)
D = sqrt(25)
D = 5

You might be interested in

A factory uses 1/6 of a barrel of raisins in each batch of granola bars. Yesterday, the factory used 1/2 of a barrel of raisins.

balu736 [363]

1/6 = 1 batch, 2/6 = 2 batches and so on

if the factory used 1/2, the factory used 3/6 of a barrel, which equals to 3 batches.

<em>hope it helps :)</em>

8 0

2 years ago

Can someone help me with this! It would be much appreciated!!

love history [14]

Answer:

1. parallelogram

2. trapezoid

3.rectangle

4. parallelogram

5. trapezoid

6. rhombus

7.rectangle

8. rhombus

3 0

3 years ago

Model to write 30 or 40 as a mixed number

____ [38]

30 as a mixed number:
$10 \frac{200}{10}$

3 0

2 years ago

What does this equal?

anzhelika [568]

It should be about 22.55.

4 0

3 years ago

Simplify the expression below, I really just need the steps I have the answer (also can someone tell me how to edit points on th

Sloan [31]

Answer: $3x^2y\sqrt[3]{y}\\\\$

Work Shown:

$\sqrt[3]{27x^{6}y^{4}}\\\\\sqrt[3]{3^3x^{3+3}y^{3+1}}\\\\\sqrt[3]{3^3x^{3}*x^{3}*y^{3}*y^{1}}\\\\\sqrt[3]{3^3x^{2*3}*y^{3}*y}\\\\\sqrt[3]{\left(3x^2y\right)^3*y}\\\\\sqrt[3]{\left(3x^2y\right)^3}*\sqrt[3]{y}\\\\3x^2y\sqrt[3]{y}\\\\$

Explanation:

As the steps above show, the goal is to factor the expression under the root in terms of pulling out cubed terms. That way when we apply the cube root to them, the exponents cancel. We cannot factor the y term completely, so we have a bit of leftovers.

4 0

2 years ago