First we are going to express both equation in terms of
to compare their slopes:
For our first equation:
For our second equation:
So now we have our system of equations in terms of y:
Notice that the slope, the coefficient of
, in both equations is the same: 1, and if tow linear equations have the same slope, they are parallel.
We can conclude that we can classify the system of equations as
parallel.
3/5 is the correct answer for sin s
a.
This is the geometric sequence: a1 = 1.5 m = 150
cm, r = 0.74
The formula now is an = a1 x r ^ n-1
Just substitute a1 = 150 cm and r = 0.74
an = 150 x (0.74) ^ n – 1
b.
The second part is:
A6 = 150 x 0.74 ^ 6-1
= 150 x 0.74 ^5
= 150 x 0.221906624
= 33.28509936 cm
Answer:
AB = √37
BC = 2√5
AC = √41
Type: SCALENE TRIANGLE
Step-by-step explanation:
Given the coordinates
A(1, –9), B(0, –3), C(–4, –5)
We are to find the length of each sides first. Using the formula for calculating the distance between two points, we will have;
For A(1, –9) and B(0, –3)
AB = √(-3+9)²+(0-1)²
AB = √6²+(-1)²
AB = √36+1
AB = √37
For coordinates B(0, –3) and C(–4, –5)
BC = √(-5+3)²+(-4-0)²
BC= √(-2)²+(-4)²
BC = √4+16
BC = √20
BC = 2√5
For coordinates A(1, –9), C(–4, –5)
AC = √(-5+9)²+(-4-1)²
AC= √(4)²+(-5)²
AC = √16+25
AC = √41
<em>Since the sides of the triangles are all different, hence the triangle is a SCALENE triangle</em>
