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2 years ago

Whoever answers I’ll mark brainliest

Mathematics

2 answers:

qaws [65]2 years ago

8 0

Answer:

The answer is a Isosceles triangle I'm 100%

Step-by-step explanation:

i hope you have a nice day and mark me please(:

Vlad1618 [11]2 years ago

3 0

its the first 1. b.

Step-by-step explanation:

nb. b. b b b bcbcbc

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Please help with all 3 questions and show all work thank you.

Bumek [7]

1. 8+8=16
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30+16=46-perimeter
15*8=120-area
2.well the slope is 3/4 but i don't know the distance
3.y(13, -6)

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3 years ago

Read 2 more answers

What is the factored form of this expression? 4x^3 - 8x^2 - 9x + 18

natta225 [31]

Answer:

Step-by-step explanation:

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3 years ago

After a birthday party 1/3 of a large cake was left. If this piece of cake was shared equally among the 4 people, what fraction

Tomtit [17]

1/12 would be left of the cake

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1 year ago

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If we sample from a small finite population without replacement, the binomial distribution should not be used because the event

seropon [69]

Answer:

5/4324 = 0.001156337

Step-by-step explanation:

To better understand the hyper-geometric distribution consider the following example:

There are 100 senators in the US Congress, and suppose 60 of them are republicans so 100 - 60 = 40 are democrats).

We extract a random sample of 30 senators and we want to answer this question:

What is the probability that 10 senators in the sample are republicans (and of course, 30 - 10 = 20 democrats)?

The answer using the h-g distribution is:

$\large \frac{\binom{60}{10}\binom{100-60}{30-10}}{\binom{100}{30}}=\frac{\binom{60}{10}\binom{40}{20}}{\binom{100}{30}}$

Now, imagine there are 56 senators (56 lottery numbers), 6 are republicans (6 winning numbers and 50 losers), we extract a sample of 6 senators (the bettor selects 6 numbers). What is the probability that 4 senators are republicans? (What is the probability that 4 numbers are winners?).

<em>As we see, the situation is exactly the same,</em> but changing the numbers. So the answer would be

$\large \frac{\binom{6}{4}\binom{56-6}{6-4}}{\binom{56}{6}}=\frac{\binom{6}{4}\binom{50}{2}}{\binom{56}{6}}$

Now compute each combination separately:

$\large \binom{6}{4}=\frac{6!}{4!2!}=15\\\\\binom{50}{2}=\frac{50!}{2!48!}=1225\\\\\binom{50}{6}=\frac{50!}{6!44!}=15890700$

and now replace the values:

$\large \frac{\binom{6}{4}\binom{50}{2}}{\binom{56}{6}}=\frac{15*1225}{15890700}=\frac{18375}{15890700}=\frac{5}{4324}$

and that is it.

If the decimal expression is preferred then divide the fractions to get 0.001156337

6 0

3 years ago

Solve the inequality and enter your solution as an inequality comparing the

Amiraneli [1.4K]

Answer:

x - 33 < 8

x < 8 + 33

x < 41

x= {40, 39, 38, . . . }

4 0

2 years ago