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geniusboy [140]
3 years ago
14

I need answer the right one cuz idk it

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
5 0

Answer:

−6x2−20x

Step-by-step explanation:

−2(3x2+10x)

=(−2)(3x2+10x)

=(−2)(3x2)+(−2)(10x)

=−6x2−20x

elena-s [515]3 years ago
5 0

Answer:-6x^2-20x

Step-by-step explanation: multiply -2 by all factors

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3:2

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Yes a ratio is a rate

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3 years ago
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3 years ago
Log_c(A)=2<br> log_c(B)=5, <br> solve log_c(A^5B^3)
vlabodo [156]

We know that \log_a(bc)=\log_a(b)+\log_a(c).

Using this rule,

\log_c(A^5B^3)=\log_c(A^5)+\log_c(B^3).

We also know that \log_c(a^b)=b\log_c(a).

Using this rule,

\log_c(A^5)+\log_c(B^3)=5\log_c(A)+3\log_c(B)

Now we know that \log_c(A)=2,\log_c(B)=5 so,

5\cdot2+3\cdot5=10+15=\boxed{25}.

Hope this helps :)

3 0
3 years ago
Find the exact value of the following expression (without using a calculator): tan(Sin^-1 x/2)
Sati [7]

Answer:

tan(Sin^-1 x/2)=  \frac{x/2}{\sqrt{1-x^{2}/4 } }

Step-by-step explanation:

Let sin^-1 x/2= θ

then sinθ= x/2

on the basis of unit circle, we have a triangle with hypotenuse of length 1,   one side of length x/2 and opposite angle of θ.

          tan(Sin^-1 x/2) = tanθ

           tanθ= sinθ/cosθ

as per trigonometric identities cosθ= √(1-sin^2θ)

           tanθ= sinθ/ √(1-sin^2θ)

substituting the value sinθ=x/2 in the above equation

             tanθ= \frac{x/2}{\sqrt{1-x^{2}/4 } }

now substituting the value sin^-1 x/2= θ in above equation

             tan(sin^-1 x/2) =  \frac{x/2}{\sqrt{1-x^{2}/4 } }

!

3 0
3 years ago
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