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yawa3891 [41]
3 years ago
12

CAN SOMEONE PLEASE HELP ME WITH MY CHEMISTRY ASSIGNMENT.

Chemistry
1 answer:
Mazyrski [523]3 years ago
5 0

Answer:

yes its correct

Explanation:

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Question 2 (2 points)
poizon [28]

Answer:

m_w=439.2g

Explanation:

Hello!

In this case, since the by-mass percent of a solution is a measure of the mass of the solute over the mass of the solution:

\%m/m=\frac{m_{solute}}{m_{solution}} *100\%

As we know the mass of the solution and the by-mass percent, we can compute the mass of glucose in the 480 g of solution:

m_{solute}=\frac{\%m/m*m_{solution}}{100\%}

Thus, by plugging in the data, we obtain:

m_{solute}=\frac{8.5\%*480g}{100\%}=40.8g

Finally, since the solution is made up of glucose and water, we compute the mass of water as follows:

m_w=m_{sol}-m_{solute}=480g-40.8g\\\\m_w=439.2g

Best regards!

7 0
3 years ago
Which of the following is NOT a way that biodiversity is important to an ecosystem?
Vitek1552 [10]

Answer:

A. Biodiversity can increase the rate of extinction

Explanation:

That statement is false because variety is better for a better ecosystem. With variety more can survive in certain situations that others cant.

5 0
3 years ago
A sample is found to contain 57.2 % N a H C O 3 NaHCOX3 by mass. What is the mass of NaHCO 3 in 4.25 g of the sample
liq [111]

Answer:

The mass of N a H C O 3 present is 2.431 g

Explanation:

The sample contains 57.2 % N a H C O 3  by mass.

To find the mass of N a H C O 3  in the sample, we need to find what the equivalent of 57.2 %.

Mass of N a H C O 3  = Percentage Composition * Mass of sample

Mass of N a H C O 3  = 57.2 / 100     * 4.25

Mass of N a H C O 3   = 2.431 g

The mass of N a H C O 3 present is 2.431 g

3 0
4 years ago
g 32.53 g of a solid is heated to 100.oC and added to 50.0 g of water in a coffee cup calorimeter and the contents are allowed t
Radda [10]

Answer:

0.886 J/g.°C

Explanation:

Step 1: Calculate the heat absorbed by the water

We will use the following expression

Q = c × m × ΔT

where,

  • Q: heat
  • c: specific heat capacity
  • m: mass
  • ΔT: change in the temperature

Q(water) = c(water) × m(water) × ΔT(water)

Q(water) = 4.184 J/g.°C × 50.0 g × (34.4 °C - 25.36 °C) = 1.89 × 10³ J

According to the law of conservation of energy, the sum of the energy lost by the solid and the energy absorbed by the water is zero.

Q(water) + Q(solid) = 0

Q(solid) = -Q(water) =  -1.89 × 10³ J

Step 2: Calculate the specific heat capacity of the solid

We will use the following expression.

Q(solid) = c(solid) × m(solid) × ΔT(solid)

c(solid) = Q(solid) / m(solid) × ΔT(solid)

c(solid) = (-1.89 × 10³ J) / 32.53 g × (34.4 °C - 100. °C) = 0.886 J/g.°C

8 0
3 years ago
PLEASE HELP FOR THIS ASSIGNMENT
mars1129 [50]
<h2>Steps:</h2>
  • Remember that Density = mass/volume, or D = m/v

So firstly, we have to find the volume of the rock. To do this, we need to subtract the volume of water A from the volume of the water B. In this case:

  • Water A = 30 mL
  • Water B = 40 mL
  • 40 mL - 30 mL = 10 mL

<u>The volume of the rock is 10 mL.</u>

Now that we have the volume, we can plug that and the density of the rock into the density equation to solve for the mass.

3.678=\frac{m}{10}

For this, multiply both sides by 10:

36.78=m

<h2>Answer:</h2>

<u>Rounding to the tenths place, the mass of the rock is 36.8 g, or C.</u>

6 0
4 years ago
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