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melisa1 [442]
3 years ago
15

Could someone help me with all of these questions. Also plz if you don't know the answer plz don't put something that isn't righ

t because this depends on if I'm failing or not

Chemistry
1 answer:
densk [106]3 years ago
3 0
Q3.) acidic
q4.)that the solution is acidic
q5.)that the solution is alkaline
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What is specific gravity in minerals?
natima [27]

Specific gravity is the "heaviness" of a mineral. It is defined as a number that expresses the ratio between the weight of a mineral and the weight of an equal volume of water.

4 0
3 years ago
Read 2 more answers
Please help me ASAP!!!
DENIUS [597]

Answer: Patrick was so sure he was a thief because why would you knock if it was your own room you would open the door. And he didn’t have a key to open the door.

Hope this helped

Explanation:

3 0
3 years ago
The equilibrium constant for the reaction of carbon monoxide with water is 1.845. if 1.00 mol of each reactant is placed in a 2.
SpyIntel [72]
[CO] = 1 mol / 2L = 0.5 M

[
According to the equation:

and by using the ICE table:

             CO(g) + H2O(g) ↔   CO2(g) + H2(g)

initial     0.5            0.5                    0          0

change  -X              -X                   +X         +X
     
Equ       (0.5-X)       (0.5-X)                     X            X

when Kc = X^2 * (0.5-X)^2

by substitution:

1.845 = X^2 * (0.5-X)^2  by solving for X 

∴X = 0.26

∴ [CO2] = X = 0.26
4 0
3 years ago
A rigid container of gas has a pressure of 1.72 atm and temperature of 21 oC. If the temperature increases to 85 oC, what is the
Vinil7 [7]

Answer:

the new pressure is 2.09 atm

Explanation:

you have to use gay lussac's law so the formula is

p1/t1 = p2/t2

and convert C to Kelvin k=C+273.15

1.72atm/294.15 = p2/358.15

solve for p2 by multiplying 358.15 on both sides

p2=2.09 atm

5 0
3 years ago
If a buffer solution is 0.190 m in a weak acid (ka = 8.2 × 10-5) and 0.590 m in its conjugate base, what is the ph?\
Lubov Fominskaja [6]
<span>You use the Henderson - Hasselbalch equation pH = pKa + log ([salt]/[acid]) pKa = -log (8.2*10^-5) = 4.081 pH = 4.081 + (0.590/0.190) pH = 4.081 + log 3.105 pH = 4.081 + 0.49206 pH = 4.573</span>
5 0
3 years ago
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