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melisa1 [442]
3 years ago
15

Could someone help me with all of these questions. Also plz if you don't know the answer plz don't put something that isn't righ

t because this depends on if I'm failing or not

Chemistry
1 answer:
densk [106]3 years ago
3 0
Q3.) acidic
q4.)that the solution is acidic
q5.)that the solution is alkaline
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what pressure is generated when 5 mol of ethane is stored in a volume of 8 dm 3 at 25°C? Base calculations on each of the follow
Goshia [24]

Answer:

a) 40,75 atm

b) 30,11 atm

Explanation:

The Ideal Gas Equation is an equation that describes the behavior of the ideal gases:

                                     PV = nRT

where:

  • P = pressure [atm]
  • V = volume [L]
  • n = number of mole of gas [n]
  • R= gas constant = 0,08205 [atm.L/mol.°K]
  • T=absolute temperature [°K]

<em>Note: We can express this values with other units, but we must ensure that the units used are the same as those used in the gas constant.</em>

The truncated virial equation of state, is an equation used to model the behavior of real gases. In this, unlike the ideal gas equation, other parameters of the gases are considered as the <u>intermolecular forces</u> and the <u>space occupied</u> by the gas

\frac{Pv}{RT} = 1 + \frac{B}{v}

where:

  • v is the molar volume [L/mol]
  • B is the second virial coefficient [L/mol]
  • P the pressure [atm]
  • R the gas constant = 0,08205 [atm.L/mol.°K]

a) Ideal gas equation:

We convert our data to the adecuate units:

n = 5 moles

V = 3 dm3 = 3 L

T = 25°C = 298°K

We clear pressure of the idea gas equation and replace the data:

PV = nRT ..... P = nRT/V = 5 * 0,08205 * 298/3 =40,75 atm

b) Truncated virial equation:

We convert our data to the adecuate units:

n = 5 moles

V = 3 dm3 = 3 L

T = 25°C = 298°K

B = -156,7*10^-6 m3/mol = -156,7*10^-3 L/mol

We clear pressure of the idea gas equation and replace the data:

\frac{Pv}{RT} = 1 + \frac{B}{v} ...... P = (1 + \frac{B}{v}) \frac{RT}{v}

and v = 3 L/5 moles = 0,6 L/mol

P = (1 + \frac{-156,7*10^{-3} }{0,6} ) \frac{0,08205*298}{0,6} = 30,11 atm

5 0
3 years ago
Element x reacts with oxygen to produce x2o3 in an experiment it is found that 1.0000 g of x produces 1.1xxx g of x2o3 what is t
8_murik_8 [283]

Since X is 1 g, therefore O must be 0.1 g. Therefore:

moles O = 0.1 g / (16 g / mol) = 0.00625 mol

 

We can see that for every 3 moles of O, there are 2 moles of X, therefore:

moles X = 0.00625 mol O (3 moles X / 2 moles O) = 0.009375 mol

 

Molar mass X = 1 g / 0.009375 mol

<span>Molar mass X = 106.67 g/mol</span>

4 0
3 years ago
2. A cell with few energy needs would most
sattari [20]

A Cell with few energy needs would most likely contain a small number of Mitochondria.

  • All cells require energy to function, but cells typically have significant energy needs that can only be met by the mitochondria, the cell's powerhouse.
  • They transform glucose into ATP, a chemical with a huge energy storage capacity.
  • Muscles have a large number of mitochondria, allowing them to react rapidly and powerfully to the body's ongoing need for energy.
  • Macromolecules, defunct cell components, and microbes are all digested by lysosomes.
  • Vacuoles are typically tiny and aid in the sequestration of waste.
  • The ribosome, an intercellular structure consisting of both RNA and protein, is where a cell produces new proteins.

Therefore out of all these cell organelles, the cell has fewer mitochondria for less energy need.

Learn more about cell organelles here:

brainly.com/question/13408297

#SPJ9

5 0
2 years ago
Pb(NO3)2 (aq) + 2 NaI (aq) --&gt; PbI2 (s) + 2 NaNO3 (aq)
Blizzard [7]
Pb(NO3)2 (aq) + 2 NaI (aq) --> PbI2 (s) + 2 NaNO3 (aq)
Starting with with 200.0 grams of Pb(NO3)2 and 120.0 grams of NaI:
A. What is the limiting reagent?
B. How many grams of PbI2 is theoretically formed?
C. How many grams of the excess reactant remains?
D. If 48 grams of NaNO3 actually formed in the reaction, what is the percent yield of this reaction?
8 0
3 years ago
Give the number of significant figures indicated 78
Mama L [17]

2 significant figures

6 0
3 years ago
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