The answer is 34.1 mL.
Solution:
Assuming ideal behavior of gases, we can use the universal gas law equation
P1V1/T1 = P2V2/T2
The terms with subscripts of one represent the given initial values while for terms with subscripts of two represent the standard states which is the final condition.
At STP, P2 is 760.0torr and T2 is 0°C or 273.15K. Substituting the values to the ideal gas expression, we can now calculate for the volume V2 of the gas at STP:
(800.0torr * 34.2mL) / 288.15K = (760.0torr * V2) / 273.15K
V2 = (800.0torr * 34.2mL * 273.15K) / (288.15K * 760.0torr)
V2 = 34.1 mL
<em>i think the answer is b </em>
Answer:
-32 Fahrenheit converts to 237.594 Kelvin
Answer:
36.4 atm
Explanation:
To find the pressure, you need to use the Ideal Gas Law. The equation looks like this:
PV = nRT
In this equation,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = moles
-----> R = constant (0.0821 L*atm/mol*K)
-----> T = temperature (K)
Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.
P = ? atm R = 0.0821 L*atm/mol*K
V = 5.00 L T = 393 °C + 273.15 = 312.45 K
n = 7.10 moles
PV = nRT
P(5.00 L) = (7.10 moles)(0.0821 L*atm/mol*K)(312.45 K)
P(5.00 L) = 182.130
P = 36.4 atm
