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sweet T has 2 orange picks for every 5 green.If there are 21 picks in all,How many picks are orange?

kipiarov [429]

6 of the picks are orange.

8 0

3 years ago

Can someone help me with this i have been trying for hours and i actually got the wrong answer so can you help me understand by

kap26 [50]

Answer:

C

Step-by-step explanation:

We are given that FGH is a triangle, which means that...

Angle F + Angle G + Angle H = 180

Start by substituting the given angle measurements into the equation:

4x+2+13x-7+3x+5=180

Combine like terms

20x=180

Divide both sides by 20 to isolate x

x=9

Plug 9 back in for x to solve for each angle

Angle F = 4(9)+2=36+2=38

Angle G = 13(9)-7=117-7=110

Angle H = 3(9)+5=27+5=32

7 0

2 years ago

Read 2 more answers

Someone please help??

Novay_Z [31]

Answer:

x = 1

Step-by-step explanation:

The base is 3. The value of 3^x will be 3 only when x=1.

_____

The value of any exponential term will be equal to the base when the exponent is 1.

8 0

3 years ago

An attacker at the base of a castle wall 4 m high throws a rock straight up with speed 7.5 m/s from a height of 1.5 m

Sergeu [11.5K]

Answer:

a) Yes, b) $v\approx 2.686\,\frac{m}{s}$ , c) $v_{o} \approx 7.002\,\frac{m}{s}$

Step-by-step explanation:

a) The maximum height reached by the rock is:

$\Delta y = \frac{\left(0\,\frac{m}{s} \right)^{2}-\left(7.5\,\frac{m}{s} \right)^{2}}{2\cdot \left(-9.807\,\frac{m}{s^{2}} \right)}$

$\Delta y = 2.868\,m$

$y = 1.5\,m + 2.868\,m$

$y = 4.368\,m$

Yes, the rock will exceed the top of the wall.

b) The speed when the rock reaches the top of the wall:

$v = \sqrt{\left(7.5\,\frac{m}{s} \right)^{2}+2\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (4\,m-1.5\,m)}$

$v\approx 2.686\,\frac{m}{s}$

c) The initial speed required so that stone does not exceed the top of the wall is:

$v_{o} = \sqrt{\left(0\,\frac{m}{s} \right)^{2}-2\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (4\,m-1.5\,m) }$

$v_{o} \approx 7.002\,\frac{m}{s}$

8 0

4 years ago

Before a computer is assembled, its motherboard goes through a special inspection. Assume only 85% of motherboards pass this ins

andreyandreev [35.5K]

Answer:

(a) The probability that at least 13 of the next 15 motherboards pass inspection is 0.6042.

(b) On average, 1.18 motherboards should be inspected until a motherboard that passes inspection is found.

Step-by-step explanation:

Let X = number of motherboards that pass the inspection.

The probability that a motherboards pass the inspection is P (X) = p = 0.85.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is,

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that at least 13 of the next 15 motherboards pass inspection as follows:

P (X ≥ 13) = P (X= 13) + P (X = 14) + P (x = 15)

$={15\choose 13}0.85^{13}(1-0.85)^{15-13}+{15\choose 13}0.85^{14}(1-0.85)^{15-14}\\+{15\choose 13}0.85^{16}(1-0.85)^{15-15}\\=0.2856+0.2312+0.0874\\=0.6042$

Thus, the probability that at least 13 of the next 15 motherboards pass inspection is 0.6042.

(b)

Computed the expected number of motherboards should be inspected until a motherboard that passes inspection is found as follows:

$Expected\ value=\frac{1}{p}=\frac{1}{0.85}= 1.1764\approx1.18$

Thus, on average, 1.18 motherboards should be inspected until a motherboard that passes inspection is found.

3 0

4 years ago