Answer:
Explanation:
(a) For this problem we can use the expression
where B is the magnetic field, r is the radius of the curve described by the ion, m is the mass and q is the electric charge.
In this case, both isotopes have the same velocity, and we can assume that both isotopes has been ionized to have the same charge. Being r and r' the radius of the curve for 12C ion and 14C ion respectively, we have
Hence, 2*24.67cm=49.35cm is the diameter of the orbit for 14C.
(b) we can calculate ω by using
By dividing these expressions we have
The isotope 12C has 1.16 more angular frecuency than 14C
I hope this is useful for you
regards
Use the concept of beat frequency to find the applicable final freqeuncy for 20Hz beat frequency.
Beat can be defined as 'the interference pattern between two sounds of slightly different frequencies0
The expression for beat frequency is given as
Where,
Final frequency
Initial frequency
The beat frequency for us is 25Hz and the initial frequency is 240Hz, then
Being an absolute value, two values are possible, both in addition and subtraction:
The two possible values are
Answer:
The <em><u>n = 2 → n = 3</u></em> transition results in the absorption of the highest-energy photon.
Explanation:
Formula used for the radius of the orbit will be,
where,
= energy of
orbit
n = number of orbit
Z = atomic number
Here: Z = 1 (hydrogen atom)
Energy of the first orbit in H atom .
Energy of the second orbit in H atom .
Energy of the third orbit in H atom .
Energy of the fifth orbit in H atom .
Energy of the sixth orbit in H atom .
Energy of the seventh orbit in H atom .
During an absorption of energy electron jumps from lower state to higher state.So, absorption will take place in :
1) n = 2 → n = 3
2) n= 5 → n = 6
Energy absorbed when: n = 2 → n = 3
Energy absorbed when: n = 5 → n = 6
1.89 eV > 0.166 eV
E> E'
So,the n = 2 → n = 3 transition results in the absorption of the highest-energy photon.
Answer:
a) The average friction force exerted on the toboggan is 653.125 newtons, b) The rough region reduced the kinetic energy of the toboggan in 92.889 %, c) The speed of the toboggan is reduced in 73.333 %.
Explanation:
a) Given the existence of non-conservative forces (friction between toboggan and ground), the motion must be modelled by means of the Principle of Energy Conservation and the Work-Energy Theorem, since toboggan decrease its speed (associated with due to the action of friction. Changes in gravitational potential energy can be neglected due to the inclination of the ground. Then:
Where:
,
are the initial and final translational kinetic energies of the tobbogan, measured in joules.
- Dissipated work due to friction, measured in joules.
By applying definitions of translation kinetic energy and work, the expression described above is now expanded and simplified:
Where:
- Friction force, measured in newtons.
- Distance travelled by the toboggan in the rough region, measured in meters.
- Mass of the toboggan, measured in kilograms.
,
- Initial and final speed of the toboggan, measured in meters per second.
The friction force is cleared:
If ,
,
and
, then:
The average friction force exerted on the toboggan is 653.125 newtons.
b) The percentage lost by the kinetic energy of the tobbogan due to friction is given by the following expression, which is expanded and simplified afterwards:
If and
, then:
The rough region reduced the kinetic energy of the toboggan in 92.889 %.
c) The percentage lost by the speed of the tobbogan due to friction is given by the following expression:
If and
, then:
The speed of the toboggan is reduced in 73.333 %.