Ask question

Ask question

All categories

3 years ago

14

Use the terms in the word box to label each class of lever and the diagram.

1 answer:

balu736 [363]3 years ago

3 0

1st class lever the Fulcrum is between the load and the effort
2nd class lever the load is between the effort and the fulcrum
3rd class lever the effort is between the fulcrum and the load.
1)1st class lever
2)3rd class lever
3)2nd class lever
part2
The human hands act as a fulcrum in cases where a hum is holding something in case of a person sweeping
1)1st class lever
2)2nd class lever
3)3rdclass lever.
4)1st class
5)3rd class
6)1st class
7)2nd class
8)3rd class
9)3rd class

You might be interested in

What is the wavelength of an earthquake wave if it has a speed of 7 km/s and a frequency of 3 Hz?

Phantasy [73]

V=fλ
7=3xλ
λ=7÷3
λ=2.333km

5 0

3 years ago

During lightning strikes from a cloud to the ground, currents as high as 2.50×104 A can occur and last for about 40.0 μs . How m

Nezavi [6.7K]

Answer:

<h3>The charge transferred from the cloud to earth is 1 Coulomb.</h3>

Explanation:

Given :

Current $I = 2.5 \times 10^{4}$ A

Time $t = 40 \times 10^{-6}$ sec

We know that the current is the rate of flow of charge.

From the formula of current,

<h3> $I = \frac{Q}{t}$ </h3>

Where $Q =$ charge transfer between cloud and earth.

$Q =I t$

$Q = 2.5 \times 10^{4} \times 40 \times 10^{-6}$

$Q = 1$ C

Hence, the charge transferred from the cloud to earth is 1 Coulomb.

3 0

3 years ago

What and where is the asteroid belt?<br><br> Please ANSWER THIS

Rudiy27

Answer:

The asteroid belt is a region of our solar system, between the orbits of Mars and Jupiter, in which many small bodies orbit our sun.

Explanation:

Hope this helps!

3 0

3 years ago

Read 2 more answers

If the angular velocity of the pully is -8.4rad/s at a given time, and its anglar acceleration is -2.8rad/s2, what is the angula

snow_lady [41]

Here we know that

$\omega_i = - 8.4 rad/s$

$\alpha = - 2.8 rad/s^2$

$t = 1.5 s$

now from kinematics we have

$\omega_f = \omega_i + \alpha t$

now from above all values we have

$\omega_f = (-8.4 rad/s) + (-2.8 rad/s^2)(1.5)$

$\omega_f = -8.4 + (-4.2)$

$\omega_f = -12.6 rad/s$

so final angular speed is -12.6 rad/s

6 0

3 years ago

What is newtons 3rd law? pls help!

drek231 [11]

For every actions, there is an opposite reaction.

3 0

3 years ago

Read 2 more answers