What type force is your answer in number 4

Physics

1 answer:

Alexandra [31]3 years ago

3 0

When an object is stationary all the forces acting on the object comes in equilibrium with each other.

The forces acting on a stationary object are:

Normal force (upwards)
Gravitational force (downwards)
push force
friction force

All these forces cancel out each other.

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What is the acceleration of a proton moving with a speed of 6.5 m/s at right angles to a magnetic field of 1.8 t ?

defon

The magnetic force acting on the proton is
$F=qvB \sin \theta$
where
q is the proton charge
v is its speed
B is the intensity of the magnetic field
$\theta$ is the angle between the direction of v and B; since the proton is moving perpendicular to the magnetic field, $\theta=90^{\circ}$ and $\sin \theta=1$ , so the force becomes
$F=qvB$

this force provides the centripetal force that keeps the proton in circular motion:
$m \frac{v^2}{r} = q v B$
where the term on the left is the centripetal force, with
m being the mass of the proton
r the radius of its orbit

Re-arranging the previous equation, we can find the radius of the proton's orbit:
$r= \frac{mv}{qB}= \frac{(1.67 \cdot 10^{-27} kg)(6.5 m/s)}{(1.6 \cdot 10^{-19} C)(1.8 T)}=3.77 \cdot 10^{-8}m$

And now we can calculate the centripetal acceleration of the proton, which is given by
$a_c = \frac{v^2}{r}= \frac{(6.5 m/s)^2}{3.77\cdot 10^{-8}m}=1.12 \cdot 10^9 m/s^2$

7 0

3 years ago

A gas undergoes two processes. In the first, the volume remains constant at 0.200 m3m3 and the pressure increases from 2.50×105

SVETLANKA909090 [29]

Answer:

$W = -4.95 \times 10^4\ J$