Answer:
<em>The weakest conjugate is HClO-.</em>
Explanation:
As a general rule, the stronger the Bronsted-Lowry acid, the weaker its conjugate base, and vice versa.
Acid 1: HClO is a strong acid, hence its conjugate base would be weak
Acid 2: H3PO4 is a weak acid, hence its conjugate base would be strong
Acid 3: hydrogen sulphide is also a moderately weak acid with a moderately strong conjugate base.
In order of increasing strengths:
HClO < H2S < H3PO4
In general oxidation is defined as gain of oxygen or loss of electron or hydrogen by an atom. Reduction is defined as gain of electron or hydrogen or loss of oxygen by an atom.
In a balanced redox reaction we have two half reactions
a) reduction half reaction : the oxidation number of element decreases
b) oxidation half reaction : the oxidation number of element increases
The element undergoing reduction is Pd.
the oxidation number of Pd decreases from +2 to 0
Thus the reduction half reaction will be
The Pd (II) ion will take two electrons and will give Pd (0)
Answer is
Answer:
[Al³⁺] = 1.62 M
[SO₄²⁻] = 2.43 M
Explanation:
Step 1: Given data
Molar concentration of Al₂(SO₄)₃: 0.811 M
Step 2: Write the reaction for the ionization of Al₂(SO₄)₃
Al₂(SO₄)₃(aq) ⇒ 2 Al³⁺(aq) + 3 SO₄²⁻(aq)
Step 3: Calculate the molar concentration of Al³⁺
The molar ratio of Al₂(SO₄)₃ to Al³⁺ is 1:2. The molarity of Al³⁺ is 2/1 × 0.811 M = 1.62 M.
Step 4: Calculate the molar concentration of SO₄²⁻
The molar ratio of Al₂(SO₄)₃ to SO₄²⁻ is 1:3. The molarity of SO₄²⁻ is 3/1 × 0.811 M = 2.43 M
Answer:
2 million years
Explanation:
500/2000 = 1/4, meaning the sample decayed to 1/4 of its original amount. From this, we can conclude that 2 half lives have passed.
In the problem, we are given one half life is 1 million years. Multiplying this by 2, we get that 2 half lives is 2 million years.
Answer:
Evaporated via combustion.
Explanation:
The loss on ignition (LOI) and Ash content are inorganic analytical techniques used to determine the percentage by mass of hydrocarbon in compounds. This process allows volatile matter and possibly impurities found in a material to evaporate, leaving behind the true chemical constituents of the material.
The 10kg lost could be moisture content of the tree, or other volatile matter which has escaped on combustion of the tree.