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Murrr4er [49]
3 years ago
7

What is the mass of 1 mole of MgSO4?

Chemistry
1 answer:
White raven [17]3 years ago
7 0

Answer:

120.37 g

Explanation:

Mg = 24.31 g

S = 32.06 g

4 O = 16 X 4 = 64 g

Therefore, MgSO4 is (24.31 + 32.06 + 64) g = 120.37 g

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Which element is more reactive in water?<br><br> -Na<br><br> -Mg
Marina86 [1]

Answer:

sodium

Explanation:

sodium is the second most reactive. Magnesium being the least reactive

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How do you determine if something is extensive or intensive
Shalnov [3]

Answer:

Intensive properties do not depend on the quantity of matter. Examples include density, state of matter, and temperature. Extensive properties do depend on sample size. Examples include volume, mass, and size.

Explanation:

Brainly!!!

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The answer to the question is B......
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Solid aluminum metal reacts with aqueous zinc chloride to produce solid zinc metal and aqueous aluminum chloride
yuradex [85]

Answer:

2Al + 3ZnCl₂    →    3Zn + 2AlCl₃

Explanation:

Chemical equation:

Al + ZnCl₂    →    Zn + AlCl₃

Balanced Chemical equation:

2Al + 3ZnCl₂    →    3Zn + 2AlCl₃

This is the example of single displacement reaction. Al displace the zinc and form aluminium chloride and zinc metal.

There are two Al three zinc and six chlorine atoms on both side of equation so it is correctly balanced.

Thus it completely follow the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by french chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

7 0
3 years ago
A 51.24-g sample of Ba(OH)2 is dissolved in enough water to make 1.20 liters of solution. How many mL of this solution must be d
g100num [7]

Answer:

0.40 L

Explanation:

Calculation of the moles of Ba(OH)_2 as:-

Mass = 51.24 g

Molar mass of Ba(OH)_2 = 171.34 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{51.24\ g}{171.34\ g/mol}

Moles= 0.2991\ mol

Volume = 1.20 L

The expression for the molarity is:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.2991\ mol}{1.20\ L}=0.24925\ M

Thus,

Considering

Molarity_{working\ solution}\times Volume_{working\ solution}=Molarity_{stock\ solution}\times Volume_{stock\ solution}

Given  that:

Molarity_{working\ solution}=0.100\ M

Volume_{working\ solution}=1\ L

Volume_{stock\ solution}=?

Molarity_{stock\ solution}=0.24925\ M

So,  

0.100\ M\times 1\ L=0.24925\ M\times Volume_{stock\ solution}

Volume_{stock\ solution}=\frac{0.100\times 1}{0.24925}\ L=0.40\ L

<u>The volume of 0.24925M stock solution added = 0.40 L </u>

6 0
3 years ago
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