At STP what is the volume of 16.34 grams of nitrogen gas?

Chemistry

1 answer:

nika2105 [10]1 year ago

6 0

Answer:

Volume = 13.06 L

Explanation:

We are given: mass of nitrogren gas = 16.34 g

We know: molar mass of nitrogen gas = 28.014 g/mol

: ideal gas law constant = 0.082 L.atm/K.mol

At STP: temperature = 273.15 K

: pressure = 1 atm

We first determine the number of moles of nitrogen gas:

n = m/M

= 16.34/28.014

= 0.58 mol

Using the ideal gas law:

$\begin{gathered} PV\text{ = nRT} \\ \\ \therefore V\text{ = }\frac{nRT}{P}\text{ = }\frac{0.58\times0.082\times273.15}{1}\text{ = 13.06 L} \end{gathered}$

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