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atroni [7]
4 years ago
8

What is the molecular formula of a compound with an empirical formula of C4H9 and a gram-formula mass of 114.0 g/mole?

Chemistry
1 answer:
hodyreva [135]4 years ago
6 0
The formula is easy:

Gram formula mass
----------------------------
Emprical Formula

So if we plug in our own numbers,

114.0
--------
57.116 

We get an answer of 1.99, which rounds to 2.
Then, we distribute based off of our empirical formula.

2(C4H9) becomes C8H18.

Our molecular formula is C8H18.
Hope I could help!
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What do the 14th Amendment and the Civil Rights Act of 1866 have in common?A. They were ways Congress sought to guarantee blacks
ehidna [41]
A. They were ways Congress sought to guarantee blacks the full rights of citizenship.
8 0
3 years ago
What happens when an ecosystem reaches the maximum number of individuals it can support
tangare [24]

Answer:

A collapse of the population is rotting, food is not enough and livelihoods have become unfeasible to decrease the number of individuals again.

Another way is to generate mutations to generate a species more vulnerable to decreasing numbers.

In this way the overpopulation is controlled.

Explanation:

In ecosystems, if an increased population breaks the balance of this and begins a new constant adaptation of the extinction of some and overpopulation of others, which may be some chains break or remain unstable.

6 0
3 years ago
You weigh out 0.1183 g of a complex salt to analyze for the percentage of cyanide ion in your complex salt. After dissolving the
Stels [109]

Answer:

25.35%

Explanation:

Again let me restate the the equation of the reaction;

H2O (ℓ) + 2 MnO4 - (aq) + 3 CN- (aq) → 2 MnO2 (s) + 3 CNO- (aq) + 2 OH- (aq)

Amount of potassium permanganate  reacted = 10.2/1000 * 0.08035 = 8.1957 * 10^-4 moles

If 2 moles of MnO4 - reacts with 3 moles of CN-

8.1957 * 10^-4 moles of MnO4 - reacts with 8.1957 * 10^-4 * 3/2

= 1.229 * 10^-3 moles of CN-

Mass of CN- reacted = 1.229 * 10^-3 moles of CN- * 26.02 g/mol

= 0.03 g

Hence, percentage of the cyanide = 0.03 g/0.1183 g * 100

= 25.35%

8 0
3 years ago
Identify the ion ratios needed to form neutral compounds from the ions below. The metal ion (cation) is listed first, and the no
Natasha2012 [34]
To figure out the ratios of these compounds, it is important to remember that the charge of these compounds must be <em>neutral</em>.

So in order to make them neutral, you must have specific ratios:

Na^{+}: Br^{-}  =1:1; This is true because they both have a charge of magnitude of 1.

Al^{3+}: Cl^{-}=1:3; We need 3 chlorine atoms because we need to balance out the charge from the 3+ charge of aluminum - therefore since chlorine has a 1- charge, we need 3 atoms.

Mg^{2+}: O^{2-}=1:1; The charges of the magnesium (2+) are balanced with the oxygen charge (2-).

Al^{3+}: O^{2-}=2:3; This is correct because if charges are like this, you must find the least common factor in order to know the ratio. The LCF is 6, therefore, for the atom with a 3+ charge, you need 2 of them, and for the atom with a 2- charge, you need 3 of them. This keeps the charge neutral.

7 0
3 years ago
Read 2 more answers
HELP! ASAP! Iron (Fe) and copper (II) chloride (CuCl2) combine to form iron (III) chloride (FeCl3) and copper (Cu). If you start
Helga [31]

Answer: 30.978

Explanation:

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7 0
3 years ago
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