Question

Draw the Lewis structure for XeCl2 and answer the following questions.

Answer 1

Answer:

Valence electrons in XeCl2 = 8 + 7 + 7 = 22.

Bonding electrons = 4.

Nonbonding electrons = 18.

Explanation:

Hello.

In this case, you can see the Lewis structure on the attached picture, in which you can see that there are since xenon has 8 valance electrons and each chlorine has 7 valence electrons, the total amount of valence electrons is:

Valence electrons in XeCl2 = 8 + 7 + 7 = 22.

Moreover, since each chlorine atom is bonding with one of the eight electrons of xenon (Lewis structure), we can see there are 4 bonding electrons.

Finally, since there are six nonbonding electrons per chlorine atom and six nonbonding electrons in xenon, the overall nonbonding electrons are:

Nonbonding electrons in XeCl2 = 6 + 6 + 6 = 18.

Regards.