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dolphi86 [110]
3 years ago
6

I need help on homework

Chemistry
1 answer:
My name is Ann [436]3 years ago
3 0
What do you need help with
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a compound has 15.39 g of gold for every 2.77 g of chlorine. simplified there is _____ g of gold for every 1 g of chlorine
iren [92.7K]

Answer:

There is 5.56 g of gold for every 1 g of chlorine

Explanation:

The ratio is the relationship between two numbers, defined as the ratio of one number to the other. So, the ratio between two numbers a and b is the fraction \frac{a}{b}

You know that a compound has 15.39 g of gold for every 2.77 g of chlorine. This can be expressed by the ratio:

\frac{15.39 g  of gold}{2.77 g of chlorine}

The proportion is the equal relationship that exists between two reasons and is represented by:    \frac{a}{b}=\frac{c}{d}

This reads a is a b as c is a d.

To calculate the amount of gold per 1 g of chlorine, the following proportion is expressed:

\frac{15.39 g  of gold}{2.77 g of chlorine}=\frac{mass of gold}{1 g of chlorine}

Solving for the mass of gold gives:

mass of gold=1 g of chlorine*\frac{15.39 g  of gold}{2.77 g of chlorine}

mass of gold= 5.56 grams

So, <u><em>there is 5.56 g of gold for every 1 g of chlorine</em></u>

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10940? Sorry if it isn’t correct
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The modern periodic table is different from Mendeleevs in several ways. In which way are the two tables the same?
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The organization is based off solitaire and many of the elements are the same
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Which has the largest atomic size selenium or oxygen?
kolbaska11 [484]

Answer:

Selenium

Explanation:

selenium has 4 energy levels (think a 4 story building) while oxygen only has 2 (think 2 story building). which one is taller?

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d. Specific heat capacity of the substance

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