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shepuryov [24]
3 years ago
13

The answer to this................

Mathematics
1 answer:
pochemuha3 years ago
3 0
Plot a point at the y-intercept of -2 or y = -2
--------------------------------------------------------------------
From there make a straight horizontal line 
---------------------------------------------------------------
Then Shade the upper-half of that line one color This shaded part stands for
Y > -2
-----------------------------------------------------------------------
Shade the lower half a different color, this stands for y ≤ 6
-------------------------------------------------------------------------
That should be it!
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Add 4x²y,-2xy²,-5xy²,3x²y plz explain​
Vinil7 [7]
4x^2 - 2xy^2
5xy^2 +
3x^2y
_____________
12x^5y^4-2xy^2

This is so because 4+5+3 is 12, then using laws of indices to add your x and y you get x^5 and y^4

To simplify your answer to the lowest you have it in the form of
3x^2y^2(4x^2y - 2xy^2)

If you multiply this as well you get the same answer I got with the addition
3 0
3 years ago
You went to a bake sale and bought a whole bunch of
MakcuM [25]

Answer:

If cookies are for $1 and brownies are for $2, let number of cookies = x and number of brownies = y

∴ $1*(x*1) + $2*(y*1) = $13

Step-by-step explanation:

1) You can buy 4 brownies for $2 each = 2*4 = $8

The rest you can buy cookies = 5 cookies = $5

$8+$5=$13

2) You can buy 5 brownies and 3 cookies = $10+$3 = $13

3) You can buy 3 brownies and 7 cookies = $6+$7=$13

Equation: -

If cookies are for $1 and brownies are for $2, let number of cookies = x and number of brownies = y

∴ $1*(x*1) + $2*(y*1) = $13

7 0
3 years ago
Need help ASAP !!!!!
AnnyKZ [126]
What do you need help with?
8 0
3 years ago
Find all 6 trig functions given the terminal side goes through point (0,-3)
d1i1m1o1n [39]
So hmm notice the picture below

that's (0, -3)

now, keep in mind, adjacent is 0, opposite is -3, and hypotenuse, or radius, is 3

and recall  sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\ \quad \\

% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}

8 0
3 years ago
HEEEEEEELLLPPPPPPPPP!!!!! PLEASEEEEEEEE
Klio2033 [76]

Answer:

a) a_n=2(a_{n-1}), where a_1=5.

b)  a_n=5(2)^{n-1}

Step-by-step explanation:

The given sequence is


5,10,20,40....


The first term of the sequence is

a_1=5


The second term is a_2=10


The common ratio for this sequence can be determined using any two consecutive terms in the sequence.

Using the first two terms, the common ratio is

r=\frac{a_2}{a_1}


\Rightarrow r=\frac{10}{5}=2


a) The recursive rule is given by,


a_n=r(a_{n-1})


a_n=2(a_{n-1}), where a_1=5.


b) The explicit rule is given by a_n=a_1r^{n-1}


\Rightarrow a_n=5(2)^{n-1}





3 0
3 years ago
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