Answer:
In the above experiment, these three flies are not enough cogent
Explanation:
Because in the above experiment which is designed to test that, in the above cage these three flies prefer which type of food either it is a banana which is fresh or either apple which is rotten. But the behavior of the flies is not the same, so it is difficult to judge where the flies spend more time. It is a probability that the flies spend most of the on a fresh banana or a rotten apple or both fruits.
These three flies could be unusual.
Admitting that the "a" is a capital A for normal pigmentation and "d" is a capital D for dimpled chin, meaning that these are the dominant traits, the fraction expected to be albino with a non-dimpled chin is of 1/16.
When two heterozygous are crossed and two characteristics are being analysed, the offspring quantity that will possess the two recessive traits can be represented by 1/16. This is easily confirmed when a Punnett square is made. Considering that both parents were heterozygous, on both sides of the crossing in the Punnett square, you would have the following alleles' combination: AD, Ad, aD, and ad. The offspring that would be homozygous recessive (aadd) would correspond to only 1/16.
Answer:
grasshopper
The organisms that eat the producers are the primary consumers. ... The primary consumers are herbivores (vegetarians
Answer:Ahingas are secondary consumers in a food web.
Explanation:They are carnivores and there diet includes tadpoles, frog eggs, young alligators, water snakes, etc.
Answer:
the animal cell will burst
Explanation:
If the salt solution in the animal cell is 30%, it means the water is at a 70% concentration. Outside is 20%, so the water is 80%.
Water will enter the cell. Water is at a higher concentration outside the cell (80%) or a lower concentration inside the cell (70%) by the process of osmosis.
Eventually, the animal cell will burst, because it does not have any cell wall to control the swelling of the cell that occurs as water flows in.