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Pavlova-9 [17]
4 years ago
13

mrs.jackson gives the table below to her students in order for the function to be linear what must m be and why?​

Mathematics
1 answer:
Hunter-Best [27]4 years ago
7 0

M or the slope has to be constant throughout the graph. This is because in order for a line to be linear it has to be increasing or decreasing at the same rate. So it the slope was 2 from point x 1 -2 then the slope changed to 1 from 3-4 it would not be linear. :)

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How do you do this problem? Please explain.
horrorfan [7]

Answer:  8.632

<u>Step-by-step explanation:</u>

First, you need to find the length of AE. Since ΔAEC is a right triangle, we can use:

sin\ C=\dfrac{AE}{AC}\\\\\\sin\ 50 = \dfrac{AE}{5}\\\\\\5\ sin\ 50=AE\\\\3.83=AE

Next, Use Heron's formula to find the Area of ΔADE.

  • AE = 3.83
  • ED = 6
  • AD = 9

Heron's formula is:

A=\sqrt{s(s-a)(s-b)(s-c)}\quad \text{where}\ s = \dfrac{a+b+c}{2}\\\\s=\dfrac{AE+ED+AD}{2}=\dfrac{3.83+6+9}{2}=\dfrac{18.83}{2}=9.415\\\\A=\sqrt{9.415(9.415-3.83)(9.415-6)(9.415-9)}\\\\.\quad=\sqrt{9.415(5.585)(3.415)(0.415)}\\\\.\quad=\sqrt{74.519}\\\\.\quad=8.632

5 0
3 years ago
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Phoenix [80]

Answer:

Letter c is the answer

Step-by-step explanation:

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7 0
3 years ago
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Joe is making a ramp.Find the length of the ramp if the height is 7meters and the base is 24 meters
Musya8 [376]

Answer:

the length of the ramp is 25 meters

Step-by-step explanation:

Joe is making a ramp. Ramp forms a right angle triangle with the base

So we use Pythagorean theorem to find the length of the ramp

AC^2(hypotenuse) = AB^2 + BC^2

Length of ramp is the hypotenuse = \sqrt{height^2 + base^2}

=\sqrt{7^2 +24^2}

= \sqrt{49 + 576^2}

= \sqrt{625}

= 25

so the length of the ramp is 25 meters

8 0
3 years ago
How many 1/4 are in 36?
densk [106]

Just turn the fraction into decimal form. Which is 0.25.

Divide 36 by 0.25

Answer=144

8 0
4 years ago
P is a point on the x axis 13 units from the point (-3, 5). find all the possible coordinates for p.
SVEN [57.7K]

If P is a point in the x axis therefore this means that the y must be zero. Hence the coordinate of p is (x, 0).

We can use the distance formula to solve for the value of x:

d^2 = (x – x1)^2 + (y – y1)^2

13^2 = (x + 3)^2 + (0 – 5)^2

169 = (x + 3)^2 + 25

(x + 3)^2 = 144

x + 3 = ± 12

x = -15, 9

 

Hence P has two possible coordinates:

<span>(-15, 0) and (9, 0)</span>

8 0
3 years ago
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