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vlabodo [156]
3 years ago
5

I don’t get it. Use the net to find the lateral area of the prism.

Mathematics
1 answer:
sesenic [268]3 years ago
6 0

the net is pretty much the net of a long box, kinda like the one in the example in the picture below.  Due to that, we can pretty much assume the two sides sticking up and down, are just two small 6x3 rectangles, namely, they have a height of 3, reason why we assume that, if that if we fold the other sides to make out the box, those two sides sticking out, must be 3m to neatly snugfit.


now, if we close the box as it stands, the sides(laterals) will be on the left-right sides two 3x15 rectangles, and on the front-back sides, two 6x15 rectangles.


we're excluding the top and bottom sides, because those are not "laterals", or sides of the box.


\bf \stackrel{\textit{two rectangles, left and right}}{2(3\cdot 15)}+\stackrel{\textit{two rectangles, front and back}}{2(6\cdot 15)}
\\\\\\
90+180\implies 270

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the quadratic function h (t)=-16t^2+150 models a balls height, in feet, over time, in seconds, after it is dropped from a 15 sto
natulia [17]
Hello! Lets solve this :)
So for the first question :
h(t) = -16t^2 + 150
h(0)= -16 (0)^2 + 150
h(0)= -16(0) + 150
h(0)= 0 + 150
h(0)= 150 feet

Second question
We need to find here the time when the ball hit the ground; or when the height h(t) is 0.
In equation form
h(t) --> 0=16t^2 + 150
16t^2 = 150
t^2=150/16
t= <span>√150/16
t= 5</span><span>√6/4
t= 5 (2.45)/4
t= 3.06 seconds
</span>
Hope this helps! If you have any other questions or would like further explanation just let me know! :)



3 0
3 years ago
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